我正在用matplotlib生成一个条形图.这一切都很好但我无法弄清楚如何防止x轴的标签相互重叠.这是一个例子:

以下是postgres 9.1数据库的一些示例SQL:
drop table if exists mytable;
create table mytable(id bigint, version smallint, date_from timestamp without time zone);
insert into mytable(id, version, date_from) values
('4084036', '1', '2006-12-22 22:46:35'),
('4084938', '1', '2006-12-23 16:19:13'),
('4084938', '2', '2006-12-23 16:20:23'),
('4084939', '1', '2006-12-23 16:29:14'),
('4084954', '1', '2006-12-23 16:28:28'),
('4250653', '1', '2007-02-12 21:58:53'),
('4250657', '1', '2007-03-12 21:58:53')
;
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这是我的python脚本:
# -*- coding: utf-8 -*-
#!/usr/bin/python2.7
import psycopg2
import matplotlib.pyplot as plt
fig = plt.figure()
# for savefig()
import pylab
###
### Connect to database …Run Code Online (Sandbox Code Playgroud) 我正在根据matplotlib-demo创建一个饼图:https://matplotlib.org/1.2.1/examples/pylab_examples/pie_demo.html
每个的百分比frac似乎是自动标记的.如何用绝对值替换饼图上绘制的这些自动标记的相对值(%)fracs[]?
我想是从generate_series,每个月的统计和计数的ID在每月的总和.这个SQL适用于PostgreSQL 9.1:
SELECT (to_char(serie,'yyyy-mm')) AS year, sum(amount)::int AS eintraege FROM (
SELECT
COUNT(mytable.id) as amount,
generate_series::date as serie
FROM mytable
RIGHT JOIN generate_series(
(SELECT min(date_from) FROM mytable)::date,
(SELECT max(date_from) FROM mytable)::date,
interval '1 day') ON generate_series = date(date_from)
WHERE version = 1
GROUP BY generate_series
) AS foo
GROUP BY Year
ORDER BY Year ASC;
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这是我的输出
"2006-12" | 4
"2007-02" | 1
"2007-03" | 1
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但我想得到的是这个输出(1月份的"0"值):
"2006-12" | 4
"2007-01" | 0
"2007-02" | 1
"2007-03" | 1
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因此,如果有一个月没有id,那么它应该被列出.任何想法如何解决这个问题?
以下是一些示例数据: …
我在postgresql 9.1中有一个带有housenumber的示例表:
drop table if exists mytable;
create table mytable(road_id int, housenr text);
insert into mytable(road_id, housenr) values
('11', '1' ),
('22', '12' ),
('33', '99/1' ),
('44', '88' ),
('55', '2' ),
('66', '28' ),
('77', '29')
;
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现在我必须将整个列"housenr"转换为INT字段.SQL中是否有一种方法只能从可以转换的列中转换这些行.在mytable中,除了"housenr"= 99/1之外,这将是每一行.
类似于:FOR EACH ROW IF :: int IS POSSIBLE将行ELSE REMOVE FROM TABLE转换为