小编Nas*_*Nas的帖子

//create inflater
final LayoutInflater inflater = (LayoutInflater) this
                .getSystemService(Context.LAYOUT_INFLATER_SERVICE);
//create popupwindow
    PopupWindow pw=new PopupWindow(inflater.inflate(R.layout.menu, (ViewGroup)findViewById(R.layout.dictionarylist)));

        Button Menu = (Button) findViewById(R.id.Menu);
        Menu.setOnClickListener(new Button.OnClickListener() {
            public void onClick(View v) {
                pw.showAtLocation(v, Gravity.CENTER, 0, 0);
                pw.update(0, 0, 200, 250);
                pw.setOutsideTouchable(false);
            }
        });

我想要的是当我单击父活动中的按钮时显示弹出窗口.当弹出按钮时,弹出窗口有按钮,它可以执行某些功能.

//创建layoutinflator试试{

        LayoutInflater inflator = LayoutInflater.from(this);

//创建视图

        final View menuview = inflater.inflate(R.layout.menu,
                (ViewGroup) findViewById(R.layout.dictionarylist));

        Button Menu = (Button) findViewById(R.id.Menu);

        Menu.setOnClickListener(new Button.OnClickListener() {
            public void onClick(View v) {

                final PopupWindow pw = new PopupWindow(menuview);//initialize popupwindow

                pw.showAtLocation(v, Gravity.CENTER, 0, 0);
                pw.update(0, 0, 200, 250);
                pw.setOutsideTouchable(false);//set outside touch to false

// onclick监听popupwindow中的按钮

                Button b1 = (Button) menuview.findViewById(R.id.btnClose);
                b1.setOnClickListener(new OnClickListener() {

                    // @Override
                    public void onClick(View v) {
                        pw.dismiss();

                    }

                });
                Button b2 = (Button) menuview.findViewById(R.id.btnQuiz);
                b2.setOnClickListener(new OnClickListener() {

                    // @Override
                    public void onClick(View v) …