我尝试在jQuery中创建一个simpel形式的valitation函数,但在某种程度上,这个函数总是返回de输入为false.你能帮我吗？
<!DOCTYPE html>
<html lang="en">
<head>
<title>Bootstrap Example</title>
<meta charset="utf-8">
<meta name="viewport" content="width=device-width, initial-scale=1">
<link rel="stylesheet" href="http://maxcdn.bootstrapcdn.com/bootstrap/3.3.6/css/bootstrap.min.css">
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.12.4/jquery.min.js"></script>
<script src="http://maxcdn.bootstrapcdn.com/bootstrap/3.3.6/js/bootstrap.min.js"></script>
<style>input.notoke { border: 1px solid red; }</style>
</head>
<body>
<script>
$(document).ready(function(){
$("form#validate :input").each(function(){
$(this).on("change paste keyup", function() {
if ( $(this).val().match( $(this).attr('data-regex') ) ){
$(this).removeClass('notoke');
} else {
$(this).addClass('notoke');
}
});
});
});
</script>
<div class="container-fluid">
<div class="row">
<div class="col-sm-12">
<h3>Formulier</h3>
<form role="form" id="validate">
<div class="form-group">
<label for="email">Email address:</label>
<input type="text" class="form-control" id="email" data-regex="^[A-Z0-9._%+-]+@[A-Z0-9.-]+.[A-Z]{2,4}$">
</div>
<div class="form-group">
<label for="pwd">Password:</label> …