我正在使用:
似乎我的配置文件没有被加载,每次我调用mapper.map我得到AutoMapper.AutoMapperMappingException:'缺少类型映射配置或不支持的映射.
这是我的Startup.cs类的ConfigureServices方法
// This method gets called by the runtime. Use this method to add services to the container.
public void ConfigureServices(IServiceCollection services)
{
services.AddMvc();
//register automapper
services.AddAutoMapper();
.
.
}
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在另一个名为xxxMappings的项目中,我有我的映射配置文件.示例类
public class StatusMappingProfile : Profile
{
public StatusMappingProfile()
{
CreateMap<Status, StatusDTO>()
.ForMember(t => t.Id, s => s.MapFrom(d => d.Id))
.ForMember(t => t.Title, s => s.MapFrom(d => d.Name))
.ForMember(t => t.Color, s => s.MapFrom(d => d.Color));
}
public override string ProfileName
{
get …Run Code Online (Sandbox Code Playgroud) 任何人都可以告诉我如何使用XStream序列化HashMap?
private HashMap<String,String> attributes;
attributes = new HashMap<String,String>();
attributes.put("Description","Value");
attributes.put("Description2","Value2");
attributes.put("Description3","Value3");
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我的xml看起来像
<attributes>
<entry>
<string>Description</string>
<string>value</string>
</entry>
<entry>
<string>Description2</string>
<string>Value2</string>
</entry>
<entry>
<string>Description3</string>
<string>Value3</string>
</entry>
</attributes>
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我想要一个输出
<attributes>
<attr>
<description>Description</description>
<value>Value</value>
</attr>
<attr>
<description>Description2</description>
<value>Value2</value>
</attr>
<attr>
<description>Description3</description>
<value>Value</value>
</attr>
</attributes>
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怎么用XStream实现呢?是否可以注释?
我有一个kendo组合框,并且还有一个带值的变量.如何在组合框中搜索值,如果存在,请选择它?全部使用javascript/Jquery
http://jsfiddle.net/mspasiuk/8HnnZ/
var movieId=10;
var combo =$("#movies").kendoComboBox({
dataTextField: "text",
dataValueField: "value",
dataSource: data,
height: 100
});
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我找不到如何设置值和Id.所以我的问题是如何将selectedIndex或Value设置为我所拥有的,如果不存在,则将selectedIndex设置为-1
我有一个API调用返回的JSON数组
[{
"id": 1,
"name": "aa",
"zone": 1
}, {
"id": 2,
"name": "bb",
"zone": 1
}, {
"id": 3,
"name": "cc",
"zone": 2
}, {
"id": 3,
"name": "dd",
"zone": 2
}
]
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通过使用lodash,我_.groupBy(myData,'zone')得到了一个对象,其中包含2个数组,每个数组用于一个不同的区域。但是我需要实现的是,在一个包含区域数组并且每个区域都有一个关联名称数组的对象中。
所需结果:
[
{
"zone": "1",
"items": [
{
"id": 1,
"name": "aa",
"zone": 1
},
{
"id": 2,
"name": "bb",
"zone": 1
}
]
},
{
"zone": "2",
"items": [
{
"id": 3,
"name": "cc",
"zone": 2
},
{
"id": 3,
"name": "dd", …Run Code Online (Sandbox Code Playgroud) angular ×1
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