我有一个这样的字典:
myDict = {
'BigMeadow2_U4': (1609.32, 22076.38, 3.98),
'MooseRun': (57813.48, 750187.72, 231.25),
'Hwy14_2': (991.31, 21536.80, 6.47)
}
如何获得我的指示中每个项目的第一个值？
我想最后一个清单:
myList = [1609.32,57813.48,991.31]
我有一个访问Github API的Python Flask应用程序.为此,我需要存储访问令牌.存储该数据的常见做法是什么？如何在我的应用程序中访问该数据？
from flask import Flask, request
app = Flask(__name__)
app.config['DEBUG'] = True
@app.route('/',methods=['POST'])
def foo():
...
我正在尝试基于各种解决方案在虚拟环境中安装GDAL .
但是下载本身已经失败:
$ pip install --no-install GDAL
这是pip.log
------------------------------------------------------------
/Users/test/venv/bin/pip run on Sun Jun 2 15:35:15 2013
Downloading/unpacking GDAL
Running setup.py egg_info for package GDAL
running egg_info
writing pip-egg-info/GDAL.egg-info/PKG-INFO
writing top-level names to pip-egg-info/GDAL.egg-info/top_level.txt
writing dependency_links to pip-egg-info/GDAL.egg-info/dependency_links.txt
warning: manifest_maker: standard file '-c' not found
Traceback (most recent call last):
File "<string>", line 16, in <module>
File "/Users/test/venv/build/GDAL/setup.py", line 267, in <module>
ext_modules = ext_modules )
File "/usr/local/Cellar/python/2.7.5/Frameworks/Python.framework/Versions/2.7/lib/python2.7/distutils/core.py", line 152, in setup
dist.run_commands()
File "/usr/local/Cellar/python/2.7.5/Frameworks/Python.framework/Versions/2.7/lib/python2.7/distutils/dist.py", line 953, …给这样的字典
testDict = {76: [4], 32: [2, 4, 7, 3], 56: [2, 58, 59]}
我如何获得最长列表的密钥？在这种情况下,它会32.
我有一个烧瓶应用程序大致如下所示:
app = Flask(__name__)
@app.route('/',methods=['POST'])
def foo():
data = json.loads(request.data)
# do some stuff
return "OK"
现在另外我想从该脚本每隔十秒运行一个函数.我不想为此睡觉.我还有以下芹菜脚本:
from celery import Celery
from datetime import timedelta
celery = Celery('__name__')
CELERYBEAT_SCHEDULE = {
'add-every-30-seconds': {
'task': 'tasks.add',
'schedule': timedelta(seconds=10)
},
}
@celery.task(name='tasks.add')
def hello():
app.logger.info('run my function')
该脚本工作正常,但不执行logger.info.我错过了什么？
如何制作标题不是粗体的markdown表？
| content 1 | babbad |
|content2 | dsfa |
| content 3 | safds |
给出一个列表作为值的字典.
myDict = {0: [0, 1, 2], 1: [], 2: [20, 25, 26, 28, 31, 34], 3: [], 4: [0, 1, 2, 3, 4, 7, 10], 5: [], 6: [10, 20, 24]}
如果值列表为空,如何从字典中删除项目？
我试图遍历字典并删除项目,但在迭代期间不允许更改字典大小.
for item in myDict:
if myDict[item] == []:
print item
del myDict[item]
我有一个生成numpy数组的循环:
for x in range(0, 1000):
myArray = myFunction(x)
返回的数组总是一维的.我想将所有数组合并为一个数组(也是一维数组).
我试过以下,但失败了
allArrays = []
for x in range(0, 1000):
myArray = myFunction(x)
allArrays += myArray
错误是ValueError: operands could not be broadcast together with shapes (0) (9095).我怎么能让它工作？
例如这两个数组:
[ 234 342 234 5454 34 6]
[ 23 2 1 4 55 34]
应该合并到这个数组:
[ 234 342 234 5454 34 6 23 2 1 4 55 34 ]
我正在尝试删除目录中的几个文件。
到目前为止，我有该代码：
for filename in glob.glob("buffer*" ):
os.remove(filename)
for filename in glob.glob("grid*" ):
os.remove(filename)
for filename in glob.glob("OSMroads*" ):
os.remove(filename)
for filename in glob.glob("newCostSurface*" ):
os.remove(filename)
for filename in glob.glob("standsLine*" ):
os.remove(filename)
for filename in glob.glob("standsReprojected*" ):
os.remove(filename)
有办法提高效率吗？