合并从循环返回的numpy数组

Question

我有一个生成numpy数组的循环:

for x in range(0, 1000):
   myArray = myFunction(x)

返回的数组总是一维的.我想将所有数组合并为一个数组(也是一维数组).

我试过以下,但失败了

allArrays = []
for x in range(0, 1000):
   myArray = myFunction(x)
   allArrays += myArray

错误是ValueError: operands could not be broadcast together with shapes (0) (9095).我怎么能让它工作？

例如这两个数组:

[ 234 342 234 5454 34 6]
[ 23 2 1 4 55 34]

应该合并到这个数组:

[ 234 342 234 5454 34 6 23 2 1 4 55 34 ]

Answer 1

你可能意味着

allArrays = np.array([])
for x in range(0, 1000):
    myArray = myFunction(x)
    allArrays = np.concatenate([allArrays, myArray])

更简洁的方法(参见wims的答案)是使用列表理解,

allArrays = np.concatenate([myFunction(x) for x in range]) 

Answer 2

您应该知道返回数组的形状。假设， myArray.shape = (2, 4) 然后

allArrays = np.empty((0, 4))
for x in range(0, 1000):
    myArray = myFunction(x)
    allArrays = np.append(allArrays, myArray, axis = 0)

Answer 3

allArrays = np.concatenate([myFunction(x) for x in range(1000)])