小编Dea*_*ver的帖子

我几周前使用数组编写了这个程序,现在我需要使用指针而不是使用数组.我不确定如何去做,所以任何提示将不胜感激!谢谢!:d

这是代码:

#include <stdio.h>

int showArray(int row);
int exchangeRow(int row1, int row2);

int x, y;
int array[10][10];
int j;
int k;
int inputrow;
int inputcolumn;
int scanrow;
int temp;
int row1;
int row2;

int main() {

    // Initialize array
    for(j = 0; j < 10; j++) {
          printf("\n");
          for(k = 0; k < 10; k++) {
                array[j][k] = j * 10 + k;
                printf("%d ", array[j][k]);
          }
    }
    printf("\n \n");

    // Print out selected row
    printf("Type in a number for …

我试图比较两个字符串,其中第一个字符串是数组的单个元素,第二个数组只是一个常规字符串.出于某种原因,这种比较并非如此.希望有人可以指出我正确的方向!

empty =  "        " 
pawn =   "  Pawn  " 
rook =   "  Rook  " 
knight = " Knight " 
bishop = " Bishop " 
queen =  "  Queen " 
king =   "  King  "

emptyspot = {} 
for i = 1, 8 do
    emptyspot[i] = {}
    for j = 1, 8 do
        emptyspot[i][j] = "    /    "   
    end 
end

function chessBoard() 
    io.write("\n\nWelcome to LuaChess!\n\n") 
    io.write("          1        2        3        4        5        6        7        8    \n") 
    io.write("      *************************************************************************\n") 
    io.write("      *".. empty …