小编chr*_*ags的帖子

Firebase Storage / Google Places - async - await support

I am moving my swift project to Swift 5.5, taking advantage of async await and trying to learn the syntax effectively while I am at it.

I have been successful so far in moving some functions across - those within the FirebaseFirestore database: ".getDocuments()" and ".setData".

In these instances, the compiler recognizes what I am trying to do and suggests the 'async throws' version of the method, leaving out the completion parameter / closure. See screen shot here: Xcode 给了我使用异步抛出而不是闭包的选项。

When I …

async-await google-places-api swift firebase-storage

5
推荐指数
0
解决办法
294
查看次数

SwiftUI NavigationLink 控制台错误(SwiftUI 在推送 aNavigationLink 时遇到问题。请提交错误。)

尝试以编程方式触发导航链接时遇到上述错误的问题。单击链接后,错误的目标数组元素将偶尔加载(相对于单击的标签),当然会显示上述错误。

当我以非编程方式触发导航链接时,不会发生错误,但当用户单击此链接时,我需要运行另一种方法。

我已经阅读了几个问题,例如此处此处,但找不到我的案例的原因。

模型结构:

struct Place: Identifiable {
var id: UUID = UUID()
var name: String = ""
var testBool: Bool = false
Run Code Online (Sandbox Code Playgroud)

}

环境对象的类:(生产项目有许多属性和方法 - 本质上这是 ViewModel)

class UserPlaces: ObservableObject {
@Published var placesArray: [Place] = [Place]([Place(name: "Christian", testBool: false),Place(name: "Catherine", testBool: true)])
Run Code Online (Sandbox Code Playgroud)

}

导航布尔类:(生产项目这里有许多属性,我想将它们保留在一个类中)

class Navigation: ObservableObject {
@Published var showPlaceDetail: Bool = false
Run Code Online (Sandbox Code Playgroud)

}

ContentView:(NavigationView所在的父视图)

import SwiftUI
Run Code Online (Sandbox Code Playgroud)

结构ContentView:视图{

var body: some View {
    
    NavigationView {
        
        ScrollView {
            
            Text("Hello, world!")
                .padding()
            CardsGrid2()
            
        } // …
Run Code Online (Sandbox Code Playgroud)

swiftui swiftui-navigationlink

3
推荐指数
1
解决办法
1873
查看次数