我想从坐标值中获取位置名称.这是代码,
- (void)viewWillAppear:(BOOL)animated {
CLLocationCoordinate2D zoomLocation;
zoomLocation.latitude = 39.281516;
zoomLocation.longitude= -76.580806;
MKCoordinateRegion viewRegion = MKCoordinateRegionMakeWithDistance(zoomLocation, 0.5*METERS_PER_MILE, 0.5*METERS_PER_MILE);
MKCoordinateRegion adjustedRegion = [_mapView regionThatFits:viewRegion];
[_mapView setRegion:adjustedRegion animated:YES];
}
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所以,从纬度和经度来看,我想知道位置名称.
我想从我的iPhone应用程序发布一个图像到pinterest帐户,没有任何API发布,因为我试图将它与URL Scheme集成,但没有成功.这是代码,
- (void)pinThroughURLScheme {
NSString *urlString = PinterestURLMake(self.image, nil, @"alt", @"image.jpeg", NO);
[[UIApplication sharedApplication] openURL:[NSURL URLWithString:urlString]];
}
NSString *PinterestURLMake(UIImage *image, NSString *urlString, NSString *alt, NSString *title, BOOL isVideo) {
NSString *base64ImageString = [NSString stringWithFormat:@"data:image/png;base64,%@", NSStringFromUIImage(image)];
NSString *encodedBase64ImageString = [base64ImageString urlEncodeUsingEncoding:NSUTF8StringEncoding];
NSString *encodedURLValue = [urlString urlEncodeUsingEncoding:NSUTF8StringEncoding];
NSString *encodedAltValue = [alt urlEncodeUsingEncoding:NSUTF8StringEncoding];
NSString *encodedTitleValue = [[NSString stringWithFormat:@"%@ %.0fx%.0f pixels", title, image.size.width, image.size.height] urlEncodeUsingEncoding:NSUTF8StringEncoding];
NSString *videoValue = isVideo ? @"true" : @"false";
return [NSString stringWithFormat:@"pinterest://pin/create/bookmarklet/?url=URL-OF-THE-PAGE-TO-PIN&media=URL-OF-THE-IMAGE-TO-PIN&description=ENTER-YOUR-DESCRIPTION-FOR-THE-PIN",
encodedBase64ImageString,
urlString ? [NSString stringWithFormat:@"&url=%@", encodedURLValue] : …Run Code Online (Sandbox Code Playgroud) 我想按文件名对所有 NSDocumentDirectory 进行排序,但文件夹应该首先按名称排序,然后所有文件按名称排序。
在我的文档目录中,我也有很多文件和文件夹。
我有这样的数组,
_filePathsArray =[[NSFileManager defaultManager] contentsOfDirectoryAtPath:_selectedPath error:Nil];
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提前致谢
我正在使用推特和iOS 5帐户框架.问题是我无法使用http://api.twitter.com/1/friends/ids.json?screen_name=%@ "这个api 获取朋友列表但是从twitter api explorer,我得到了朋友列表.(twitter explorer api = https://dev.twitter.com/console).
我正在开发一个应用程序,在它作为客户端要求,很少有视图兼容iPhone 4设备,其他视图兼容iPhone 4,5/iPad.那么在单一构建中是否可能?
我知道这是不可能的,但我想要你的建议.如果您有任何与此相关的链接,请与我分享.
ios ×4
iphone ×4
ios5 ×1
ipad ×1
mapkit ×1
nsarray ×1
objective-c ×1
pinterest ×1
url-scheme ×1
xcode ×1