我正在尝试通过单击列表中的链接来进行烟雾测试。第一次访问后，测试停止并出现以下错误。
CypressError: cy.click() failed because this element is detached from the DOM.
<a href="/link2">...</a>
Cypress requires elements be attached in the DOM to interact with them.
The previous command that ran was:
> cy.wrap()
我该怎么做才能保持循环中的元素？
it('Click each link in the list', () => {
cy.get('li a').each(($el, index, $list) => {
cy.wrap($el).click();
cy.go(-1);
})
})
测试的目的是检查列表中的所有页面是否都没有出现 404 错误。按照html代码
<ul>
<li><a href="/link1">Link 1</a></li>
<li><a href="/link2">Link 2</a></li>
<li><a href="/link3">Link 3</a></li>
</ul>
我试图在应用程序的单独日志文件中编写不同类型的条目.由于我试图找出的原因,所有条目都出现在所有日志文件中.我能做错什么？
我想只有关键条目进入/tmp/log/critical.log并调试条目进入/tmp/log/debug.log文件,而所有的进入者都可以进入/tmp/log/all.log日志文件.
以下是/etc/rsyslog.conf文件中的条目
local0.* /tmp/log/all.log
local0.alert /tmp/log/alert.log
local0.crit /tmp/log/critical.log
local0.debug /tmp/log/debug.log
local0.emerg /tmp/log/emergency.log
local0.err /tmp/log/error.log
local0.info /tmp/log/info.log
local0.notice /tmp/log/notice.log
local0.warning /tmp/log/warning.log
我的示例c程序编写syslog条目...
#include<syslog.h>
main()
{
openlog("myapp",LOG_CONS|LOG_PID|LOG_NDELAY,LOG_LOCAL0);
syslog(LOG_EMERG|LOG_LOCAL0,"Emergency",getuid());
syslog(LOG_ALERT|LOG_LOCAL0,"Alert",getuid());
syslog(LOG_CRIT|LOG_LOCAL0,"Critical",getuid());
syslog(LOG_ERR|LOG_LOCAL0,"Error",getuid());
syslog(LOG_WARNING|LOG_LOCAL0,"Warning",getuid());
syslog(LOG_NOTICE|LOG_LOCAL0,"Notice",getuid());
syslog(LOG_INFO|LOG_LOCAL0,"Information",getuid());
syslog(LOG_DEBUG|LOG_LOCAL0,"Debug",getuid());
closelog();
}
而不是循环遍历数组的每个元素,是否可以只遍历具有赋值的元素？
在下面的例子中,我想只遍历三个元素而不是循环遍历数组中的每个元素.我有什么选择？我讨厌在基于某些逻辑分配给他们的少数元素时循环遍历数千个元素.
main()
{
int i, intArray[10000];
intArray[334] = 30;
intArray[563] = 50;
intArray[989] = 90;
for (i = 0; i < 10000; i++)
{
printf("%d\n", intArray[i]);
}
}
感谢您阅读该帖子.对不起,如果重新发布.我在论坛中找不到类似的问题.
以下是我的应用程序的自定义路由.有没有更好的方法或组织它们？我不想在添加新模块时创建一组自定义路由.理想情况下,我希望在不定义其中任何一个的情况下采取行动.由于我的网址深度不足,我不会利用默认的Controller/Action /:id路由.
添加大量自定义路线是否会影响应用性能？帮助赞赏.
'get /location/:locationId/equipment/new' : 'LocationController.equipmentNew',
'get /location/:locationId/equipment/create' : 'LocationController.equipmentCreate',
'get /location/:locationId/equipment/edit/:id' : 'LocationController.equipmentEdit',
'get /location/:locationId/equipment/update/:id' : 'LocationController.equipmentUpdate',
'get /location/:locationId/equipment/list' : 'LocationController.equipmentList',
'get /location/:locationId/equipment/show/:id' : 'LocationController.equipmentShow',
'get /location/:locationId/equipment/delete/:id' : 'LocationController.equipmentDelete',
'get /location/:locationId/employee/new' : 'LocationController.employeeNew',
'get /location/:locationId/employee/create' : 'LocationController.employeeCreate',
'get /location/:locationId/employee/edit/:id' : 'LocationController.employeeEdit',
'get /location/:locationId/employee/update/:id' : 'LocationController.employeeUpdate',
'get /location/:locationId/employee/list' : 'LocationController.employeeList',
'get /location/:locationId/employee/show/:id' : 'LocationController.employeeShow',
'get /location/:locationId/employee/delete/:id' : 'LocationController.employeeDelete',
'get /location/:locationId/manager/new' : 'LocationController.managerNew',
'get /location/:locationId/manager/create' : 'LocationController.managerCreate',
'get /location/:locationId/manager/edit/:id' : 'LocationController.managerEdit',
'get /location/:locationId/manager/update/:id' : 'LocationController.managerUpdate',
'get /location/:locationId/manager/list' : 'LocationController.managerList',
'get …有没有一种安全的方法来检查用户是否已登录应用程序而不是检查用户的计算机中是否存在"sid"cookie？
我想让用户只有在登录后才能继续浏览页面上的某些链接.
我在服务器端进行登录验证,但希望避免请求行程.
纯JS或JQuery解决方案将不胜感激.
谢谢.