我安装在我的apache2服务器wordpress网站上,但所有固定链接都不起作用(404找不到)我的.htaccess是由wp生成的
# BEGIN WordPress
<IfModule mod_rewrite.c>
RewriteEngine On
RewriteBase /
RewriteRule ^index\.php$ - [L]
RewriteCond %{REQUEST_FILENAME} !-f
RewriteCond %{REQUEST_FILENAME} !-d
RewriteRule . /index.php [L]
</IfModule>
# END WordPress
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我对此网站的conf文件:
<Directory /home/sergey/siteName>
Options Indexes FollowSymLinks MultiViews
AllowOverride None
Order allow,deny
allow from all
</Directory>
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谢谢.
UPD:
感谢Justin Iurman的评论.在我的conf中设置AllowOverride All解决问题:)
如何确保所有html标签都已关闭?问题出现是因为我想为每篇文章创建一些摘录.例如,有人写了这样的文章:
Hi everyone, I'm just an article and I have few <strong>tags</strong> inside <em>of me</me>
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如果我在"标签"之后剪切此消息,我会得到一个未封闭的标签.在将Django保存到数据库之前,如何检查所有用户的输入文本?
将django升级到1.7后,我无法执行管理命令update_index.
Traceback (most recent call last):
File "/opt/pycharm-3.4.1/helpers/pydev/pydevd.py", line 1733, in <module>
debugger.run(setup['file'], None, None)
File "/opt/pycharm-3.4.1/helpers/pydev/pydevd.py", line 1226, in run
pydev_imports.execfile(file, globals, locals) # execute the script
File "/home/tochium/projects/povary/manage.py", line 10, in <module>
execute_from_command_line(sys.argv)
File "/home/tochium/projects/povary/local/lib/python2.7/site-packages/django/core/management/__init__.py", line 385, in execute_from_command_line
utility.execute()
File "/home/tochium/projects/povary/local/lib/python2.7/site-packages/django/core/management/__init__.py", line 377, in execute
self.fetch_command(subcommand).run_from_argv(self.argv)
File "/home/tochium/projects/povary/local/lib/python2.7/site-packages/django/core/management/base.py", line 288, in run_from_argv
self.execute(*args, **options.__dict__)
File "/home/tochium/projects/povary/local/lib/python2.7/site-packages/django/core/management/base.py", line 338, in execute
output = self.handle(*args, **options)
File "/home/tochium/projects/povary/src/django-haystack/haystack/management/commands/update_index.py", line 184, in handle
return super(Command, self).handle(*items, **options)
File "/home/tochium/projects/povary/local/lib/python2.7/site-packages/django/core/management/base.py", line …Run Code Online (Sandbox Code Playgroud) 我们的团队试图创建Telegram Bot,这对于使长消息中的电话号码可点击是至关重要的。有时我们必须向用户发送包含大量信息和少量电话号码的消息,因此很难获得电话,因为电报仅允许复制整个消息。如果我们发送没有任何减价的短消息,则电报移动应用将突出显示它:
await bot.send_message(chat_id, "Example text with a phone +79991234567")
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如果我们使用Markdown Telegram,还可以使数字可点击:
await bot.send_message(
chat_id,
"Example text with a phone [+79991234567](tel:+79991234567)",
parse_mode='Markdown'
)
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尽管如果消息是很长的电报,请忽略数字并不进行解析:
await bot.send_message(
chat_id,
"Example text with a phone [+79991234567](tel:+79991234567)\nwithin a long-long message\nwithin a long-long message\nwithin a long-long message\nwithin a long-long message\nwithin a long-long message\nwithin a long-long message\nwithin a long-long message\nwithin a long-long message\nwithin a long-long message\nwithin a long-long message",
parse_mode='Markdown'
)
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有没有一种方法可以使Telegram将电话号码显示为链接?谢谢