小编Gab*_*eek的帖子

我花了3天的时间来查看这个,我找不到一个可靠的答案.我想捕获调试消息,然后将它们输出到列表日志.我想用C#做这个.希望社区的一些帮助指出我正确的方向.

我测试了单例模式的实现,我觉得我无法弄清楚为什么IntelliJ会给我一个错误.这是代码.

public class CowSingleton {
    private static CowSingleton unique;
    private CowSingleton(){}

    //Only create new object if NOT already instantiated.

    public static CowSingleton getInstance(){
        if (unique == null){
            //creating unique object
            unique = new CowSingleton();
            System.out.println(unique);
        }
        //return Object
        return unique;
    }

    public String cowMoo(String str)
    {
       return str;
    }
}

以下是我如何称呼它:

CowSingleton cowSingleton = new CowSingleton.getInstance();
System.out.println(cowSingleton.cowMoo("Moooooo"));

我得到的错误:

"java: /Users/gpendleton/Personal/MyAnimals/src/Main.java:25: cannot find symbol
symbol  : class getInstance
location: class CowSingleton"