小编use*_*427的帖子

我试图将通配符传递给mockito any()方法.这是方法

selectGatewayInfoConfig(Operation<?> o)

我想要做的是:

when(gatewayConfigSelector.selectGatewayInfoConfig( any(**!!!!!! HERE I NEED THIS WILDCARD !!!!**));
                .thenReturn(...something...);

提前致谢.

如何在ItelliJ IDEA中生成DAO类是否有任何可能性？我发现了许多关于生成实体但没有关于如何生成DAO的文章.

我使用的是11.1.2版本.

我正在尝试使用父maven模块ism-maven创建一个maven模块web_service_client.该模块包含生成的WS类.我什么都没改变.我正在使用IntelliJ IDEA 11.1.2.

这是我的web_service_client的pom.xml.

    <?xml version="1.0" encoding="UTF-8"?>
<project xmlns="http://maven.apache.org/POM/4.0.0"
         xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
         xsi:schemaLocation="http://maven.apache.org/POM/4.0.0 http://maven.apache.org/xsd/maven-4.0.0.xsd">
    <parent>
        <artifactId>ism-maven</artifactId>
        <groupId>sk.tuke.ism</groupId>
        <version>1.0</version>
    </parent>
    <modelVersion>4.0.0</modelVersion>

    <artifactId>web_service_client</artifactId>


</project>

在我运行web_service_client的maven编译之后,我收到了这个错误:

[ERROR] Failed to execute goal org.apache.maven.plugins:maven-compiler-plugin:2.3.2:compile (default-compile) on project web_service_client: Compilation failure: Compilation failure:
[ERROR] \Users\Marek\Dropbox\ism-maven\web_service_client\src\main\java\sk\tuke\ism\webclient\Service1.java:[46,8] cannot find symbol
[ERROR] symbol  : constructor Service(java.net.URL,javax.xml.namespace.QName,javax.xml.ws.WebServiceFeature[])
[ERROR] location: class javax.xml.ws.Service
[ERROR] \Users\Marek\Dropbox\ism-maven\web_service_client\src\main\java\sk\tuke\ism\webclient\Service1.java:[54,8] cannot find symbol
[ERROR] symbol  : constructor Service(java.net.URL,javax.xml.namespace.QName,javax.xml.ws.WebServiceFeature[])
[ERROR] location: class javax.xml.ws.Service
[ERROR] \Users\Marek\Dropbox\ism-maven\web_service_client\src\main\java\sk\tuke\ism\webclient\Service1.java:[62,8] cannot find symbol
[ERROR] symbol  : constructor Service(java.net.URL,javax.xml.namespace.QName,javax.xml.ws.WebServiceFeature[])
[ERROR] location: class javax.xml.ws.Service
[ERROR] -> [Help …

我想用静态内容实现一个简单的Web服务器(如apache).服务器必须通过用户名和密码或IP地址提供身份验证.

源代码或任何有用的教程将非常有用.

谢谢你的回答.