我想从Java代码中调用这个程序get_data_Q1包并显示输出,可以任何人请帮助我.提前致谢.ult_pkg
CREATE OR REPLACE PACKAGE ult_pkg
AS
TYPE t_all_record is record (
x_object_type_id number,
x_object_name varchar2(100),
x_object_id varchar2(70),
x_audit_timestamp timestamp(6),
x_payload clob
);
--table type to hold table data after querying
type tt_all_tab is table of t_all_record index by binary_integer;
--declaration pocedures
procedure get_data_Q1(x_object_id in varchar2 , x_all_type out tt_all_tab );
end ult_pkg;
/
--body of 'ult_pkg' package
create or replace package body ult_pkg
AS
--procedure taking 'object_id' as input parameter and gives out table …我是Apache Derby数据库的新手,
当我尝试使用以下命令创建新数据库时,我遇到了以下问题
C:\>java org.apache.derby.tools.ij
ij version 10.10
ij> connect 'jdbc:derby:Mynewdb;create=true';
Mon Mar 03 20:17:32 IST 2014 Thread[main,5,main] java.io.FileNotFoundException: derby.log
(Access is denied)
----------------------------------------------------------------
Mon Mar 03 20:17:33 IST 2014:
Booting Derby version The Apache Software Foundation - Apache Derby - 10.10.1.1 - (1458268): instance a816c00e-0144-886a-02f2-000000b8d0b0
on database directory C:\Mynewdb with class loader sun.misc.Launcher$AppClassLoader@11b86e7
Loaded from file:/C:/db-derby-10.10.1.1-bin/db-derby-10.10.1.1-bin/lib/derby.jar
java.vendor=Sun Microsystems Inc.
java.runtime.version=1.6.0_23-b05
user.dir=C:\
os.name=Windows 7
os.arch=x86
os.version=6.1
derby.system.home=null
Database Class Loader started - derby.database.classpath=''
嗨,我是JQM的新手,我正在尝试在JQM登录页面上工作.
任何人可以帮助我如何进行表单验证并在用户名和密码文本框下面显示错误,如果它们是空的,并且当登录无效时我必须在表单顶部显示它作为错误消息.
这是我的HTML:
<!DOCTYPE html>
<html>
<head>
<title>Login Page</title>
<meta name="viewport" content="width=device-width, height=device-height, initial-scale=1.0"/>
<link rel="stylesheet" href="jquery.mobile/jquery.mobile-1.4.2.min.css" />
<script src="jquery.mobile/jquery.js"></script>
<script src="js/login1.4.2.js"></script>
<script src="jquery.mobile/jquery.mobile-1.4.2.min.js"></script>
</head>
<body>
<input type="hidden" id="session_key" />
<div data-role="page" id="login" class="" data-ajax="false">
<div data-role="header" >
<h3>Login Page</h3>
</div>
<div data-role="main" class="ui-content" >
<form id="check-user" data-ajax="false" class="ui-bar ui-bar-a ui-corner-all" >
<fieldset >
<div class="ui-field-contain" >
<label for="username" class="required">Enter your username:</label>
<input type="text" value="" name="username" id="username"/>
<label for="password">Enter your password:</label>
<input type="password" value="" name="password" id="password" />
</div>
<button class="ui-btn …我有一个1维数组,如:
var abc = ['a','a','b','a','c']
现在我想要取回所有索引'a',即0,1和3.
有没有简单的解决方案？
PS
我知道IndexOf或jQuery.inArray().但他们只返回了第一个匹配元素的索引