小编m00*_*0se的帖子

我从网络摄像头捕获图像,对它们进行一些繁重的处理,然后显示结果.为了保持帧率高,我想让不同帧的处理并行运行.

所以,我有一个'制片人',它捕捉图像并将它们添加到'inQueue'; 它还需要来自'outQueue'的图像并显示它:

public class Producer
{
    Capture capture;
    Queue<Image<Bgr, Byte>> inQueue;
    Queue<Image<Bgr, Byte>> outQueue;
    Object lockObject;
    Emgu.CV.UI.ImageBox screen;
    public int frameCounter = 0;

    public Producer(Emgu.CV.UI.ImageBox screen, Capture capture, Queue<Image<Bgr, Byte>> inQueue, Queue<Image<Bgr, Byte>> outQueue, Object lockObject)
    {
        this.screen = screen;
        this.capture = capture;
        this.inQueue = inQueue;
        this.outQueue = outQueue;
        this.lockObject = lockObject;
    }

    public void produce()
    {
        while (true)
        {
            lock (lockObject)
            {
                inQueue.Enqueue(capture.QueryFrame());

                if (inQueue.Count == 1)
                {
                    Monitor.PulseAll(lockObject);
                }
                if (outQueue.Count > 0)
                {
                    screen.Image = outQueue.Dequeue(); …