小编one*_*run的帖子

我想从这样的控制台运行测试(在任何目录中,dll可以是不同的.NET版本):

$ nunit3-console test.dll

我google了很多,但找不到如何设置这个.官方教程没有任何用处,完全为零,跟随它让我无处可去:https://github.com/nunit/docs/wiki/Installation

1.启动应用程序时出错

Could not load file or assembly 'System.Net.Http, Version=4.0.0.0, Culture=neutral, PublicKeyToken=b03f5f7f11d50a3a' or one of its dependencies. The system cannot find the file specified.

Stack Trace: 


[FileNotFoundException: Could not load file or assembly 'System.Net.Http, Version=4.0.0.0, Culture=neutral, PublicKeyToken=b03f5f7f11d50a3a' or one of its dependencies. The system cannot find the file specified.]
   System.Web.Http.GlobalConfiguration..cctor() +0

[TypeInitializationException: The type initializer for 'System.Web.Http.GlobalConfiguration' threw an exception.]
   System.Web.Http.GlobalConfiguration.get_Configuration() +14
   SerilogWeb.Classic.WebApi.PreApplicationStartModule.Register() +10

[InvalidOperationException: The pre-application start initialization method Register on type SerilogWeb.Classic.WebApi.PreApplicationStartModule threw an exception with the following error …

我有要映射的类,但它们没有默认的构造函数,我不希望它们有.这是因为我只映射到现有对象/从现有对象映射.

public class Order
{
    public string OrderName { get; set; }
    public Order(string name) 
    { 
        this.OrderName = name; 
    }
}

public class OrderProcessor
{
    private IService service;
    public string OrderName { get; set; }

    public OrderProcessor(IService service)
    { 
        this.service = service; 
        Mapper.Initialize(config => config.CreateMap<Order, OrderProcessor>());
    }

    public void Init()
    { 
        var order = this.service.GetOrder();

        // this works
        Mapper.Map(order, this);

        // this fails
        Mapper.Configuration.AssertConfigurationIsValid();
    }
}

AutoMapper.AutoMapperConfigurationException:找到未映射的成员.查看下面的类型和成员.添加自定义映射表达式,忽略,添加自定义解析程序或修改源/目标类型对于无匹配的构造函数,添加无参数ctor,添加可选参数或映射所有构造函数参数

订单 - > OrderProcessor(目标成员列表)

没有可用的构造函数.

在Tests.cs中的Test():行

当我不想创建新对象时,如何使配置断言传递以及失败的原因？

Resharper 2016.2

当前格式

IEnumerable<Customer> customers = dbCustomers.Select(customer => new Customer
                                                     {
                                                         Name = customer.Name,
                                                         Address = customer.Address,
                                                         Number = customer.Number
                                                     });

预期的格式

IEnumerable<Customer> customers = dbCustomers.Select(customer => new Customer
{
    Name = customer.Name,
    Address = customer.Address,
    Number = customer.Number
});

哪个Resharper 2016.2配置可以解决这个问题？

请注意,初始化器位于参数括号内,而不是变量.

如何访问Request.Properties的ActionExecutingContext？

public class UserFilter : ActionFilterAttribute
{
    public void OnActionExecuting(ActionExecutingContext actionContext)
    {
        // Properties is not part of the Request here, so I can't access it
        // Here Request is of type System.Web.HttpRequestBase
        actionContext.HttpContext.Request.Properties.Add("UserData", new UserData());
    }
}

我可以做到ApiController：

public class HomeController : ApiController
{
    public HomeController()
    {
        // Here I can do it (here Request is of type
        // System.Net.Http.HttpRequestMessage
        this.Request.Properties.Add("UserData", new UserData());
    }
}

我在'组'节点.从中,我想找到这样的'item'节点,其'id'属性等于当前'group'节点'ref_item_id'属性值.所以在我的情况下,通过在'组'节点B中,我想要'item'节点A作为输出.这有效:

<xsl:value-of select="preceding-sibling::item[@id='1']/@description"/>

但这不会(什么都不给):

<xsl:value-of select="preceding-sibling::item[@id=@ref_item_id]/@description"/>

当我输入:

<xsl:value-of select="@ref_item_id"/>

我的结果是"1".所以这个属性肯定是可访问的,但我无法从上面的XPath表达式中找到它的路径.我尝试了许多'../'组合,但无法让它工作.

要测试的代码:http://www.xmlplayground.com/7l42fo

完整的XML:

<?xml version="1.0" encoding="UTF-8"?>
<root>
    <item description="A" id="1"/>
    <item description="C" id="2"/>
    <group description="B" ref_item_id="1"/>
</root>

完整的XSLT:

<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">

<xsl:output method="text" indent="no"/>
  <xsl:template match="root">
     <xsl:for-each select="group">
        <xsl:value-of select="preceding-sibling::item[@id=@ref_item_id]/@description"/>
     </xsl:for-each>
  </xsl:template>
</xsl:stylesheet>