如何修复Resharper对象初始化程序缩进作为方法参数

Question

Resharper 2016.2

当前格式

IEnumerable<Customer> customers = dbCustomers.Select(customer => new Customer
                                                     {
                                                         Name = customer.Name,
                                                         Address = customer.Address,
                                                         Number = customer.Number
                                                     });

预期的格式

IEnumerable<Customer> customers = dbCustomers.Select(customer => new Customer
{
    Name = customer.Name,
    Address = customer.Address,
    Number = customer.Number
});

哪个Resharper 2016.2配置可以解决这个问题？

请注意,初始化器位于参数括号内,而不是变量.

Answer 1

更新到 2016.3 版本后，它刚刚开始工作，无需对 R# 设置进行任何更改。