标签: nsmutablearray

- (void)webViewDidFinishLoad:(UIWebView *)webView {
if (urlIndex == maxIndex) { 
    maxIndex = maxIndex + 1;

    NSString* sURL = webpage.request.URL.absoluteString;

    [urlHistory addObject:sURL];
    NSLog(@"%d: %@", urlIndex, [urlHistory objectAtIndex:urlIndex]);
    NSLog(@"%d: %@", urlIndex, webpage.request.URL.absoluteString);


    [sURL release];

    urlIndex = urlIndex + 1;
}
else {
    [urlHistory insertObject:webView.request.URL.absoluteString atIndex:(urlIndex - 1)];
}
}

这条线

    NSLog(@"%d: %@", urlIndex, [urlHistory objectAtIndex:urlIndex]);

print(null),同时作为这一行

    NSLog(@"%d: %@", urlIndex, webpage.request.URL.absoluteString);

打印实际的URL.

在我的initWithNibName上,我有:

- (id)initWithNibName:(NSString *)nibNameOrNil bundle:(NSBundle *)nibBundleOrNil {
self = [super initWithNibName:@"Tab1ViewController" bundle:nil];

if (self) {
    urlHistory = [[NSMutableArray alloc] init];
    urlIndex = …

我有一个数组,其中包含一些可能相同但有些不同的对象.
如何分别取出每个相同的对象和不同的对象？

下面是数组

NSMutableArray *items = [[NSMutableArray alloc]
 initWithArray:[NSArray arrayWithObjects:@"rat", @"rat", @"cat",@"Lion", @"cat", @"dog", @"dog", nil]];

我想要有四个包含这些项目的数组:

• 第一个阵列有两只老鼠
• 第二阵列有两只猫
• 第三阵列有一头狮子
• 第四阵列有两只狗

将物体拿出来的最佳方法是什么？相同的对象应放在同一个数组中.

@property(nonatomic,strong)NSMutableArray*authorMutableArray;

- (id)init {
    self = [super init];
    if (self) {

        self.authorMutableArray = [[NSMutableArray alloc] initWithObjects:@"First Row", @"Second Row", nil];

        for (NSString *string in authorMutableArray) {
            NSLog(@"String: %@", string);
        }

        NSLog(@"Init in Add Model with Author count:%i", [authorMutableArray count]);


    }
}

访问该属性的示例.NSLog始终将计数显示为0.

    - (UITableViewCellEditingStyle)tableView:(UITableView *)tableView editingStyleForRowAtIndexPath:(NSIndexPath *)indexPath
{
    if (indexPath.section == 0) { 
        if (indexPath.row == [self.addModel.authorMutableArray count] - 1 ) {
            NSLog(@"count of %i", [self.addModel.authorMutableArray count]);
            return  UITableViewCellEditingStyleInsert;
        }

        else {
            return  UITableViewCellEditingStyleDelete;

        }
    }

    else {
        return UITableViewCellEditingStyleNone; …

    NSMutableArray *tmpMutArr = [NSMutableArray arrayWithArray:allObjectsArray];
    NSLog(@"The content of array is%@",tmpMutArr);

    int index;

     for (int i=0;i<[tmpMutArr count];i++) 
     {
     if([[tmpMutArr  objectAtIndex:i] isKindOfClass:[NSDictionary class]])
     {
     NSMutableDictionary *tempDict = [tmpMutArr  objectAtIndex:i];
         if([[tempDict valueForKey:@"Name"] isEqualToString:[NSString stringWithFormat:@"%@", nameString]])
     {
     index = i;

     }
     }
     }

     [tmpMutArr replaceObjectAtIndex:index withObject:[NSDictionary dictionaryWithDictionary:mutDict]];

此代码不会像我想要的那样替换tmpMutArr中的匹配对象,而是替换tmpMutArr中的所有对象.如何只替换我想要的索引？

我知道tmpMutArr在替换之前包含所有对象,所以我只需要正确指定索引.怎么办？

我正在尝试构建一个示例应用程序,它从URL中抓取一些json并将其显​​示在表视图中.我在将数据存储到对象中并将这些对象插入NSMutableArray时遇到问题.

TableView.m

- (void) getDataFromAPI {
    NSString *endpoint = @"http://www.somesite.com/list.php";

    NSURL *url = [NSURL URLWithString:endpoint];
    NSURLRequest *request = [NSURLRequest requestWithURL:url];


    AFJSONRequestOperation *operation = [AFJSONRequestOperation JSONRequestOperationWithRequest:request success:^(NSURLRequest *request, NSHTTPURLResponse *response, id JSON) {
        [self createMovies: JSON];
    } failure:^(NSURLRequest *request, NSHTTPURLResponse *response , NSError *error , id JSON){
        UIAlertView *alert = [[UIAlertView alloc] initWithTitle:@"Alert" message:@"Uh oh, there's been a problem!" delegate:nil cancelButtonTitle:@"Cancel" otherButtonTitles:@"Retry", nil];
        [alert show];
    }];
    [operation start];
}

- (void) createMovies: (id) json {

    NSMutableArray *list = [[NSMutableArray alloc] init]; …

我有NSArray一些像以下格式的东西.

组数组是:

(
    "Q-1-A1",
    "Q-1-A9",
    "Q-2-A1",
    "Q-2-A5",
    "Q-3-A1",
    "Q-3-A8",
    "Q-4-A1",
    "Q-4-A4",
    "Q-10-A2",
    "Q-8-A2",
    "Q-9-A2",
    "Q-7-A1",
    "Q-5-A2"
)

现在我要做的是将数组元素分组这样的东西.

1 = ( "Q-1-A1","Q-1-A9")
2 = ("Q-2-A1","Q-2-A5",) ...
10 =("Q-10-A2")

任何人都可以帮助我如何实现这一目标.

提前致谢.

如何根据图像的高度对NSMutableArray图像进行排序？我是否需要找到每个图像的高度并按顺序添加它,还是有更简单的方法？

我试图从我的数组中删除一些东西,但我得到了异常

删除时无法识别的选择器

我的代码:

NSMutableArray* tempNewsArray = [[NSMutableArray alloc]init];
tempNewsArray = [[defaults objectForKey:@"NewsArray"]mutableCopy];
for(int i = 0;i< [tempNewsArray count]-1;i++)
{
if( (monthIntofNew - month <= 10 && monthIntofNew - month !=0) || ( monthIntofNew - month <= -2))
    {
        [tempNewsArray delete:[tempNewsArray objectAtIndex:i]];//exception occurs here.
        //deleted
    }
}

我想我错过了什么,请帮忙吗？

有两个可变数组,根据一些语句控制流程将对象添加到不同的可变数组中.我知道我可以使用,[theMutableArray addObject: anyObject]但我认为有点冗长.我真正需要的是[object addTo: (statement ? theMutableArrayA : theMutableArrayB)].

那么,有没有addObject被动方法？

我有一个NSMutableArray像这样的

(
   {
    Realimg = "<UIImage: 0x13951b130>, {800, 600}";
    "bid_accepted" = 1;
    "bid_amount" = 100;
    "bid_amount_num" = 100;
    "bid_cur_name" = USD;
    "bid_cur_symb" = $;
    "bid_currencycode" = 4;
    "bid_date" = "05 Nov 2015";
    "bid_msg" = testing;
    "bid_user_id" = 2;
    "nego_id" = 612;
    "pas_count" = 5;
    "ride_address" = "Sample Address";
    "ride_cover_img" = "uploadfiles/UploadUserImages/2/mobile/21426739600s-end-horton-plains.jpg";
    "ride_id" = 149;
    "ride_name" = "Ride to the World's End";
    "ride_type_id" = 0;
    "ride_type_name" = Travel;
    "ride_user_fname" = Nik;
    "ride_user_id" = 2;
    "ride_user_lname" = Mike;
   }

) …