标签: nsmutablearray

我是iphone开发的新手.我最近有一个可变数组,其中诸如标题,日期,网址和摘要等值被存储为"密钥对象".密钥是myurl,mudate,mytitle,mysummary.我想要排序参考日期的可变数组并根据那些打印所有值.我怎么能实现这一点？请帮帮我.谢谢.

            [item setObject:currentTitle forKey:@"title"];
            [item setObject:currentLink forKey:@"link"];
            [item setObject:currentSummary forKey:@"description"];
            [item setObject:currentDate forKey:@"pubDate"];//
            [item setObject:currentImage forKey:@"imagePath"];

            [recent addObject:[item copy]];

所有都是xml解析的内容.

我想从a中删除一个特定元素NSMutableArray,我看到NSArray有indexOfObject一个对此非常有用的方法,但NSMutableArray没有.

我目前的方法是使用removeObjectsInArray方法NSMutableArray作为参数传递包含我的object/s的数组.

有没有更好的方法呢？有什么理由NSMutableArray没有这种方法吗？

      for(int i=0;i<[promotionArr count];i++)
            { 
               // NSLog(@"ok");
                Promotion *prom = [[Promotion alloc]init];
                prom.pName=[[promotionArr objectAtIndex:i] objectForKey:@"name"];

                prom.pUrl=[[promotionArr objectAtIndex:i] objectForKey:@"url"];
                prom.pDescription=[[promotionArr objectAtIndex:i] objectForKey:@"description"];

                [promMUAraay addObject:prom];
                 NSLog(@"number of elements : %d",[promMUAraay count]);

 }

但元素的数量始终为0.我没有为NSMutableArray做@synthetise,xcode告诉我,我不能.我只是在我的.h中这样做

NSMutableArray *promMUAraay;

这就是问题所在？

我如何比较两个NSArray,以便我可以删除两个数组中没有的所有内容.

我试过这样的:

    NSArray *array1 = [NSArray arrayWithObjects:@"1",@"2",@"3",@"4", nil]; 
    NSArray *array2 = [NSArray arrayWithObjects:@"1",@"2",@"5",@"6", nil];

    NSMutableArray *myMutableArray = [NSMutableArray arrayWithArray:array1];
    NSMutableArray *myMutableArrayTwo = [myMutableArray copy];
    [myMutableArray removeObjectsInArray:array2];

    [array1 release];
    [array2 release];

    NSArray *array3 = [myMutableArray copy];
    [myMutableArrayTwo removeObjectsInArray:array3]; // Error here: "SIGABRT"

    NSLog(@"array3:%@",myMutableArrayTwo);

但由于错误,它不起作用.它是:" - [__ NSArrayI removeObjectsInArray:]:无法识别的选择器发送到实例0x4e51550"

我做错了什么？或者有更简单的方法来解决我的问题？谢谢您的帮助

我的数组在每个索引处包含(firstName,lastName,age).现在我想改变一个人在索引1的年龄.请指导如何做到这一点.这是我的代码.

  - (void)viewDidLoad {
[super viewDidLoad];
productArray=[[NSMutableArray alloc]init];

PersonDetail *personObj = [[PersonDetail alloc] init];
personObj.firstName = @"Adeem";
personObj.lastName = @"Basraa";
personObj.age = @"5";

[productArray addObject:personObj];
[personObj release];

PersonDetail *personObj = [[PersonDetail alloc] init];
personObj.firstName = @"Ijaz";
personObj.lastName = @"Ahmed";
personObj.age = @"10";

[productArray addObject:personObj];
[personObj release];

PersonDetail *personObj = [[PersonDetail alloc] init];
personObj.firstName = @"Waqas";
personObj.lastName = @"Ahmad";
personObj.age = @"15";
[productArray addObject:personObj];
[personObj release];

}

嗨,我正试着读一个plist的值,这就是我的plist看起来像atm

<plist version="1.0">
<array>
    <dict>
        <key>Title</key>
        <string>Mickey Mouse</string>
        <key>Image</key>
        <string>mickeymouse.png</string>
        <key>Hint1</key>
        <string>Hint 1</string>
        <key>Hint2</key>
        <string>Hint 2</string>
        <key>Hint3</key>
        <string>Hint 3</string>
    </dict>
    <dict>
        <key>Title</key>
        <string>Peter Pan</string>
        <key>Image</key>
        <string>peterpan.png</string>
        <key>Hint1</key>
        <string>Hint 1</string>
        <key>Hint2</key>
        <string>Hint 2</string>
        <key>Hint3</key>
        <string>Hint 3</string>
    </dict>
</array>
</plist>

这个我正在使用的代码然而它只是崩溃了.

AppDelegate *appDelegate = (AppDelegate *)[[UIApplication sharedApplication] delegate];
NSString *questionNumber = [NSMutableString stringWithFormat:@"Item 0"];
NSString *path = [[NSBundle mainBundle] pathForResource:@"Level1" ofType:@"plist"];
NSMutableArray *array = [[NSMutableArray alloc] initWithContentsOfFile:path];
NSDictionary *questionNumberDictionary = [array objectForKey:questionNumber];
NSString *questionTitle = [questionNumberDictionary objectForKey:@"Title"];
NSString *questionImage = [questionNumberDictionary objectForKey:@"Image"]; …

我有一个带有一些NSNumber的NSMutableArray:

{1, 2, 3, 3, 2, 1, 6, 2}

我想知道列表中出现的每个数字的出现次数.

Ex :  
1 = 2  
2 = 3  
3 = 2  
6 = 1

我NSMutablearray喜欢这个(这是一个JSON之一)

{
   "notification_list":[
      {
         "TYPE":"ARTIST",
         "ID":"07",
         "DTEXT":"Now you can listen to the songs of ARTIST1",
         "ADDEDDATE":"27th June, 2013 4:44 pm."
      },
      {
         "TYPE":"BRAND",
         "ID":"http:\/\/www.me.lk\/",
         "DTEXT":"M Entertainment have been joined with Mobile Music",
         "ADDEDDATE":"27th June, 2013 3:37 pm."
      },
      {
         "TYPE":"ARTIST",
         "ID":"03",
         "DTEXT":"Now you can listen to the songs of ARTIST2",
         "ADDEDDATE":"27th June, 2013 3:37 pm."
      },
      {
         "TYPE":"ALBUM",
         "ID":"Nava Ridgma",
         "DTEXT":"Get new album of ARTIST3, Nava ridma",
         "ADDEDDATE":"27th June, 2013 3:37 pm."
      },
      {
         "TYPE":"SONG",
         "ID":"05",
         "DTEXT":"New Song …

在NSMutableArray我要排序是这样的:

 (
        {
            "title" = "Bags";
            "price" = "$200";
        },
        {
            "title" = "Watches";
            "price" = "$40";
        },
        {
            "title" = "Earrings";
            "price" = "$1000";
        }
 )

它是一个NSMutableArray包含NSMutableArrays 的集合.我想price首先按它排序title.

NSSortDescriptor *sortByPrices = [[NSSortDescriptor alloc] initWithKey:@"price" ascending:YES];
NSSortDescriptor *sortByTitle = [[NSSortDescriptor alloc] initWithKey:@"title" ascending:YES];

[arrayProduct sortedArrayUsingDescriptors:[NSArray arrayWithObjects:sortByPrices,sortByTitle,nil]];

但是,这似乎没有用,如何对嵌套进行排序NSMutableArray？

出于某种原因,我在运行应用程序时遇到此错误:

[__NSArrayI removeAllObjects]: unrecognized selector sent to instance

我在.m中设置了NSMutableArray,如下所示:

@implementation ChooseViewController
{
    NSMutableArray *trackName;
}

并填充它像这样:

trackName = [JSON valueForKeyPath:@"results.trackName"];

但是,当我运行此代码时,它给了我错误:

[trackName removeAllObjects];

其他一切正常,trackName中的数据也可以.当我运行这段代码时,它只是搞乱了.提到的唯一的其他时间trackName数组是表视图计数:

return [trackName count];

你觉得有什么不对吗？我相信问题在于它认为它是一个NSArray,但它们都不是.