标签: iteritems

使用 pandas 版本 2，我在调用iteritems.

for event_id, region in column.iteritems():
    pass

出现以下错误消息：

Traceback (most recent call last):
     File "/home/analyst/anaconda3/envs/outrigger_env/lib/python3.10/site- 
     packages/outrigger/io/gtf.py", line 185, in exon_bedfiles
          for event_id, region in column.iteritems())
AttributeError: 'Series' object has no attribute 'iteritems'

问题：运行以下代码时出现错误。我是新手，不知道如何解决这个问题。creae 函数将每个坐标点分配给它的自治市镇。

    def find_borough(lat,lon):
        """
        return the borough of a location given its latitude and longitude
        lat: float, latitude
        lon: float, longitude
        """
        boro = 0 # initialize borough as 0
        for k,v in boros.iteritems(): # update boro to the right key corresponding to the parent polygon
            if v['polygon'].contains(Point(lon,lat)):
                boro = k
                break # break the loop once the borough is found
        return [boro]

## Analyse the cluster now
# create data frame of boroughs
    df = data1[data1.Trip_duration>=1350]
    orig_dest = …

我正在尝试读取 YAML 文件并按照文件中的顺序打印出其中的列表。

所以 YAML：

b: ...
a: ...

我的蟒蛇是：

for key, value in yaml.load(open(input_file)).items():
    print(str(key))

输出变为：

a
b

但我需要它是b那时a。我也尝试过iteritems()，得到了同样的结果。

我正在尝试创建一个总结另一个的字典.我希望仅当密钥与details_dict中的"parent"值匹配时才会更新summary_dict.我所写的内容似乎并没有像我期望的那样访问summary_dict.print语句显示它继续追加循环中的第一个iterable,而不是从summary_dict中获取正确的值.

detail_dict = {'a123': {"data": [1, 2, 3, 4], "parent": "a"},
               'a124': {"data": [1, 2, 3, 4, 5], "parent": "a"},
               'b123': {"data": [1, 2, 3], "parent": "b"},
               'b124': {"data": [1], "parent": "b"}}

summary_dict = dict.fromkeys(["a", "b"], {"data": [],
                                          "data_len": []})

for k, v in detail_dict.iteritems():
    summary_dict[v['parent']]["data"].append(v["data"])
    summary_dict[v['parent']]["data_len"].append(len(v["data"]))
    print "\nMy value is "
    print v
    print "\nMy summary dictionary now looks like:"
    print summary_dict[v['parent']]

我想要的结果字典是:

{"a": {"data": [[1, 2, 3, 4], [1, 2, 3, 4, 5]],
       "data_len": [4, 5]},
 "b": {"data": …

是否保证python 2.X的内置方法dict.items()并dict.iteritems()始终以相同的顺序返回项目？或者这些方法是非确定性的吗？

我的代码：

for column_name, column_data in summary_words.iteritems():
    if column_name != "summary" and column_name != "text" and column_name != "score" and column_name != "helpfulness":
        summary_words[column_name] = summary_words["summary"].str.count(column_name)

其中summary_words是pandas数据框，“summary”是该数据框中的一列。当我运行代码时，我收到此错误：

AssertionError：管理器项目数必须等于块项目管理器项目的并集：6004，# tot_items：6005

有谁知道我为什么会收到此错误以及如何修复它？

great   my  This    love    you best    and will    favorite    watch   ... step    succeeds    judge   (who    strictly    things, helpfulness score   summary text
0   NaN NaN NaN NaN NaN NaN NaN NaN NaN NaN ... NaN NaN NaN NaN NaN NaN 100.0   3   "There Is So Much Darkness Now ~ Come For The …