标签: formview

我有一个带有ItemTemplate的asp:FormView.我想在FormView中使用一些div元素设计内容:

<asp:FormView ID="MyFormView" runat="server" >
    <ItemTemplate>
        <div class="block1">
            Stuff...
        </div>
        <div class="block2">
            Stuff...
        </div>

        ...

        <div class="blockN">
            Stuff...
        </div>
    </ItemTemplate>
</asp:FormView>

当我运行应用程序时,会创建以下HTML:

<table id="MyFormView" style="border-collapse: collapse;" border="0" cellspacing="0">
    <tbody>
        <tr>
            <td colspan="2">
                <div class="block1">
                    Stuff...
                </div>
                <div class="block2">
                    Stuff...
                </div>

                ...

                <div class="blockN">
                    Stuff...
                </div>
            </td>
        </tr>
    </tbody>
</table>

实际上桌子有点令人不安.我不知道让ItemTemplate自由设置内容然后将其包装到表中的目的是什么.

是否可以禁用或解决此问题？(我在FormView属性中找不到标志.)

我最近遇到了FormView的问题,并发现使用get_form_kwargs的方法就是这样做.

这是我的代码:

class InternalResetPasswordView(FormView):

template_name = 'reset_password.html'
form_class = forms.InternalPasswordResetForm

# success_message = "Password was reset successfully"

# To get request object
# http://notesondjango.wordpress.com/2012/12/18/modelform-formview-and-the-request-object/
# https://stackoverflow.com/questions/13383381/show-message-after-password-change
# http://pydanny.com/simple-django-email-form-using-cbv.html
# http://bubuzzz.wordpress.com/2012/05/01/class-based-generic-views-in-django-a-simple-sample/
def get_form_kwargs(self):
    kwargs = super(InternalResetPasswordView, self).get_form_kwargs()
    kwargs['user'] = self.request.user
    return kwargs

def get_success_url(self):
    return reverse('user-detail', kwargs={'pk': self.request.user.id})

@method_decorator(login_required)
def dispatch(self, *args, **kwargs):
    return super(InternalResetPasswordView, self).dispatch(*args, **kwargs)   

'''
def get_context_data(self, **kwargs):

    context = super(InternalResetPasswordView, self).get_context_data(**kwargs)
    context['InternalPasswordResetForm'] = context.get('form')

    return context


def get_form_kwargs(self):
    kwargs = super(InternalResetPasswordView, self).get_form_kwargs()
    kwargs['request'] = self.request
    return kwargs …

定义FormView派生类时:

class PrefsView(FormView):
    template_name = "prefs.html"
    form_class = MyForm         # What's wrong with this?
    def get(self,request):
        context = self.get_context_data()
        context['pagetitle'] = 'My special Title'
        context['form'] = MyForm    # Why Do I have to write this?
        return render(self.request,self.template_name,context)

我预计context['form'] = MyForm不需要该行,因为form_class已定义,但没有它{{ form }}不会传递给模板.
我做错了什么？

在调试我正在处理的网站时,我得到了一个"黄色死亡屏幕".错误消息是"值不能为null.参数名称:键".我正在尝试将formview绑定到gridview的选定索引.当我在selectedindexchanged方法中设置断点时,所有内容似乎都正确绑定,我可以查看我的formview的值,但是当我继续运行它时,我收到上面的错误消息.我已经尝试将datakeynames属性添加到formview并获取相同的错误消息.我在这里搜索并谷歌并看到一些结果,但没有一个似乎修复或与我的问题有关.

一些代码如下:

protected void GridView1_SelectedIndexChanged(object sender, EventArgs e)
{
    lblMessage.Text = "";
    cbCalled.Visible = true;
    cbError.Visible = true;
    cbVerbal.Visible = true;
    btnSubmit.Visible = true;
    FormView1.Visible = true;
    FormView1.DataBind();
    FormView fv1 = FormView1;
    Label PathCountLabel = (Label)fv1.FindControl("pathcountLabel");
    TextBox PathResult = (TextBox)fv1.FindControl("PathResultLabel");
    if ((PathCountLabel.Text != "1 of 1 biopsies") && (PathCountLabel.Text != "Only 1 Pathology Ordered"))
    {
        PathResult.BackColor = ColorTranslator.FromHtml("#FFFFAA");
    }
}

 <asp:GridView ID="GridView1" runat="server" AutoGenerateColumns="False" 
        Visible="False" DataKeyNames="PatientID" DataSourceID="SqlDataSource1" 
        onselectedindexchanged="GridView1_SelectedIndexChanged" AllowSorting="True" onsorting="GridView1_Sorting">
    <Columns>
        <asp:CommandField ShowSelectButton="True" />
        <asp:BoundField DataField="PatientID" HeaderText="Patient Id" SortExpression="PatientID" /> …

我想将dropdownlist绑定到List<MyIem>代码后面.

 <asp:DropDownList ID="listCategories"  runat="server" Height="20px"   CssClass="CategoryDropList" SelectedValue='<%# Bind("ParentId") %>' AutoPostBack="false" Width="300px">      

不使用ObjectDataSource!

如何将其绑定到下拉列表？在什么情况下？

也SelectedValue='<%# Bind("ParentId") %>'应该工作!(我的意思是dropdownlist绑定应该在此之前发生!)

我有FormView:

<asp:FormView ID="fvReport" runat="server" DefaultMode="ReadOnly" AllowPaging="false" OnModeChanging="fvReport_ModeChanging" DataKeyNames="id">

protected void fvReport_ModeChanging(Object sender, FormViewModeEventArgs e)
    {
        switch (e.NewMode)
        {
            case FormViewMode.Edit:
                fvReport.AllowPaging = false;
                break;
        }
    }

在ItemTamplate中我放了LinkBut​​ton:

<asp:LinkButton ID="lbEdit" runat="server" CausesValidation="true" CommandName="Edit" CommandArgument='<%# Eval("id") %>'>?????????????</asp:LinkButton>

当然,FormView有EditItemTemplate部分.

当我单击Button时,FormView将刷新并保持在ReadOnly状态.我究竟做错了什么？

我在FormView控件中有一个复选框和一个面板,我需要从后面的代码中访问它们,以便使用复选框来确定面板是否可见.这是我最初使用的代码,但由于我将控件放在FormView中,它不再有效.

Protected Sub checkGenEd_CheckedChanged(ByVal sender As Object, _
                                         ByVal e As System.EventArgs)
    If checkGenEd.Checked = True Then
        panelOutcome.Visible = True
    Else
        panelOutcome.Visible = False
    End If
End Sub 

我已经开始根据我在这里查看的其他问题来解决这个问题,但是所有问题都是在C#而不是VB中,所以这就是我所得到的:

Protected Sub FormView1_DataBound(ByVal sender As Object, ByVal e As System.EventArgs) Handles FormView1.DataBound
    If FormView1.CurrentMode = FormViewMode.Edit Then

    End If
End Sub

所以,是的,我不确定如何完成它.对不起,这可能是非常基本的,但我是新来的,任何帮助都将不胜感激!

编辑:这是我现在的代码:

Protected Sub FormView1_DataBound(ByVal sender As Object, ByVal e As System.EventArgs) Handles FormView1.DataBound
    If FormView1.CurrentMode = FormViewMode.Edit Then

        CheckBox checkGenEd = formview1.FindControl("checkGenEd");
        Panel panelOutcome = formview1.FindControl("panelOutcome");

    End If
End …

我正在尝试在 Django 中实现一个 FormView，因为它似乎减少了一些样板代码。其中一个字段是文件上传字段。

class LibraryUploadLastStageForm(forms.Form):

    technician = forms.ModelChoiceField(label="prepeared by" , queryset=Technician.objects.exclude(has_left=True).order_by('name') , required=True)
    subprojects = forms.ModelChoiceField(label="Choose a subproject" , queryset=Subproject.objects.all().order_by('subproject_name') , required=True)
    lab_tracking_excel = forms.FileField(label="Choose the Lab Tracking Excel - protocol details associated with these libraries", required=False)

在 views.py 中，

class LibraryUploadFinalView(FormView):

    template_name = 'sequencing/ChooseSomething.html' 
    form_class = LibraryUploadLastStageForm


    def form_valid(self, form):
        """
        Update the library technician, and create the librarysubproject links
        """

        id_list_str = self.request.GET.get('ids')
        ids = map(int , id_list_str.split(','))

        libraries = Library.objects.filter(id__in=ids)
        print libraries.count()

        cd = form.cleaned_data
        lib_kwargs …

我尝试更新FormView时出现此错误

无法在ObjectDataSource'odsForm'中的DataObjectTypeName属性指定的类型上找到名为"MainContact.FirstName"的属性.

我认为这是因为我在EditTemplate中使用了像这样的文本框

<asp:TextBox Text='<%# Bind("MainContact.FirstName") %>' ID="txtFirstName" runat="server" />

它在文本框中显示正确的文本,但显然它在更新时不起作用.

这是FormView的数据源

<asp:ObjectDataSource ID="odsForm" runat="server" DataObjectTypeName="Helpers.BusinessObjects.EntryItem"
    SelectMethod="GetEntryByEmail" TypeName="Helpers.DataAccessers.EntryHelper"
    UpdateMethod="UpdateEntry">
    <SelectParameters>
        <asp:SessionParameter SessionField="email" Name="email" Type="String" />
    </SelectParameters>
</asp:ObjectDataSource>

这是EntryItem类

 public class EntryItem
    {
        public int Id { get; set; }
        public string Email { get; set; }
        public string Password { get; set; }
        public Person MainContact { get; set; } 
        ...
    }

和人类

public class Person
{
    public int Id { get; set; }
    public string FirstName { get; set; …

我尝试了人类已知的每个排列,我无法在iPad的模态窗体视图中正确地调整UIWebView的大小.该网页仍然显示完整的iPad纵向宽度768点.

我在哪里以及如何告诉UIWebView显示宽度540点？

我认为'scalesPageToFit'应该这样做,但它不起作用.

我尝试将Web视图设置为窗体视图的大小,即540 x 576,带有导航和状态栏.高度是无关紧要的.

我尝试将UIWebView添加到故事板中的UIView,并调整所有大小.然后我删除了UIWebView并以编程方式添加它.

- (void)viewDidLoad
{
    [super viewDidLoad];

    CGRect aFrame = self.view.frame;

    if (IS_IPAD)
    {
        aFrame = CGRectMake(0, 0, FORM_VIEW_WIDTH, FORM_VIEW_HEIGHT);
    }

    _webView = [[UIWebView alloc] initWithFrame:aFrame];
    [_webView setOpaque:NO];
    [_webView setDelegate:self];
    [_webView setScalesPageToFit:YES];

    self.view = _webView;
    ...
}

我也尝试在viewDidAppear中加载(除了viewDidLoad,viewWillAppear等)

- (void)viewDidAppear:(BOOL)animated
{
    [super viewDidAppear:animated];

    [[self webView] setFrame:CGRectMake(0, 0, FORM_VIEW_WIDTH, FORM_VIEW_HEIGHT)];
    [[self webView] setScalesPageToFit:YES];

    NSURL *webURL = [NSURL URLWithString:@"http://www.google.com"];
    NSURLRequest *request = [NSURLRequest requestWithURL:webURL cachePolicy:NSURLRequestUseProtocolCachePolicy timeoutInterval:5.0f];
    [[self webView] loadRequest:request];
}

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