我已经在SO上多次看过这次重塑2但是没有找到解决我特定问题的方法;
我有这样的数据集;
head(data)
student test score
Adam Exam1 80
Adam Exam2 90
John Exam1 70
John Exam2 60
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我试图将其转换为看起来像这样的宽格式;
Student Exam1 Exam2 ........ ExamX
Adam 80 90
John 70 60
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使用;
dcast(data,student~test,value.var='score')
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但数据最终看起来像这样的东西;
Student Exam1 Exam2
Adam 0 0
John 0 1
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有这个错误;
Aggregation function missing: defaulting to length
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任何想法为什么它将所有这些值更改为(0或1)?
我有一个整数数据帧,它是1 ... n的所有n选择3组合的子集.例如,对于n = 5,它类似于:
[,1] [,2] [,3]
[1,] 1 2 3
[2,] 1 2 4
[3,] 1 2 5
[4,] 1 3 4
[5,] 1 3 5
[6,] 1 4 5
[7,] 2 1 3
[8,] 2 1 4
[9,] 2 1 5
[10,] 2 3 4
[11,] 2 3 5
[12,] 2 4 5
[13,] 3 1 2
[14,] 3 1 4
[15,] 3 1 5
[16,] 3 2 4
[17,] 3 2 5
[18,] 3 4 5 …Run Code Online (Sandbox Code Playgroud) 我df看起来像这样:
Id Task Type Freq
3 1 A 2
3 1 B 3
3 2 A 3
3 2 B 0
4 1 A 3
4 1 B 3
4 2 A 1
4 2 B 3
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我想通过Id进行重组并得到:
Id A B … Z
3 5 3
4 4 6
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我试过了:
df_wide <- dcast(df, Id + Task ~ Type, value.var="Freq")
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并得到错误:
聚合函数缺失:默认为长度
我无法弄清楚要放什么fun.aggregate.有什么问题?
我想从以下数据中删除sessionid,qf和qn的重复组合
sessionid qf qn city
1 9cf571c8faa67cad2aa9ff41f3a26e38 cat biddix fresno
2 e30f853d4e54604fd62858badb68113a caleb amos
3 2ad41134cc285bcc06892fd68a471cd7 daniel folkers
4 2ad41134cc285bcc06892fd68a471cd7 daniel folkers
5 63a5e839510a647c1ff3b8aed684c2a5 charles pierce flint
6 691df47f2df12f14f000f9a17d1cc40e j franz prescott+valley
7 691df47f2df12f14f000f9a17d1cc40e j franz prescott+valley
8 b3a1476aa37ae4b799495256324a8d3d carrie mascorro brea
9 bd9f1404b313415e7e7b8769376d2705 fred morales las+vegas
10 b50a610292803dc302f24ae507ea853a aurora lee
11 fb74940e6feb0dc61a1b4d09fcbbcb37 andrew price yorkville
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我将数据读入data.frame并将其称为mydata.Heree是我到目前为止的代码,但我需要知道如何正确地对data.frame进行排序.其次删除sessionid,qf和qn的重复组合.最后用qf列中的直方图字符绘制图形
sortDATA<-function(name)
{
#sort the code by session Id, first name, then last name
sort1.name <- name[order("sessionid","qf","qn") , ]
#create a vector of length …Run Code Online (Sandbox Code Playgroud)