相关疑难解决方法(0)

我正在开发Windows应用商店应用程序.

我有以下手动创建的Fault类:

[XmlRoot(Namespace = "http://schemas.xmlsoap.org/soap/envelope/", ElementName = "Fault")]
public partial class SoapFault
{
    [XmlElement(Form = XmlSchemaForm.Unqualified, ElementName = "faultcode")]
    public String FaultCode { get; set; }

    [XmlElement(Form = XmlSchemaForm.Unqualified, ElementName = "faultstring")]
    public String FaultDescription { get; set; }

    [XmlElement(Form = XmlSchemaForm.Unqualified, ElementName = "detail")]
    public InnerException[] Detail { get; set; }
}

    [XmlType(Namespace = "http://my.namespace.com", TypeName = "InnerException")]
    public partial class InnerException 
    {
        [XmlElement(Form = XmlSchemaForm.Unqualified, ElementName = "message")]
        public String Message { get; set; }
    }

这是我试图阅读的服务器的回复:

<env:Envelope …

我正在尝试反序列化XML。XML示例如下

 <?xml version="1.0" ?> 
 <TRANSACTION_RESPONSE>
    <TRANSACTION>
        <TRANSACTION_ID>25429</TRANSACTION_ID> 
        <MERCHANT_ACC_NO>02700701354375000964</MERCHANT_ACC_NO> 
        <TXN_STATUS>F</TXN_STATUS> 
        <TXN_SIGNATURE>a16af68d4c3e2280e44bd7c2c23f2af6cb1f0e5a28c266ea741608e72b1a5e4224da5b975909cc43c53b6c0f7f1bbf0820269caa3e350dd1812484edc499b279</TXN_SIGNATURE> 
        <TXN_SIGNATURE2>B1684258EA112C8B5BA51F73CDA9864D1BB98E04F5A78B67A3E539BEF96CCF4D16CFF6B9E04818B50E855E0783BB075309D112CA596BDC49F9738C4BF3AA1FB4</TXN_SIGNATURE2> 
        <TRAN_DATE>29-09-2015 07:36:59</TRAN_DATE> 
        <MERCHANT_TRANID>150929093703RUDZMX4</MERCHANT_TRANID> 
        <RESPONSE_CODE>9967</RESPONSE_CODE> 
        <RESPONSE_DESC>Bank rejected transaction!</RESPONSE_DESC> 
        <CUSTOMER_ID>RUDZMX</CUSTOMER_ID> 
        <AUTH_ID /> 
        <AUTH_DATE /> 
        <CAPTURE_DATE /> 
        <SALES_DATE /> 
        <VOID_REV_DATE /> 
        <REFUND_DATE /> 
        <REFUND_AMOUNT>0.00</REFUND_AMOUNT> 
    </TRANSACTION>
  </TRANSACTION_RESPONSE>  

以下是课程

[XmlType("TRANSACTION_RESPONSE")]

public class BankQueryResponse
{
    [XmlElement("TRANSACTION_ID")]
    public string TransactionId { get; set; }

    [XmlElement("MERCHANT_ACC_NO")]
    public string MerchantAccNo { get; set; }

    [XmlElement("TXN_SIGNATURE")]
    public string TxnSignature { get; set; }

    [XmlElement("TRAN_DATE")]
    public DateTime TranDate { get; set; }

    [XmlElement("TXN_STATUS")]
    public string TxnStatus { get; set; } …

如何使用C#将以下CatalogProduct标记解除扩展到我的CatalogProduct对象？

<?xml version="1.0" encoding="UTF-8"?>
<CatalogProducts>
    <CatalogProduct Name="MyName1" Version="1.1.0"/>
    <CatalogProduct Name="MyName2" Version="1.1.0"/>
</CatalogProducts>

注意我没有CatalogProducts对象,所以想要在拉回到反序列化时跳过该元素

谢谢

如何让Student class可序列化？我正在读这篇文章,但如果我在下面的场景中实现它,我不知道什么是正确的方法.

public class Student
{
    private string _studentNumber;
    private string _lastName;
    private string _firtName;
    private List<Subject> _subjects;

    public Student() { }

    public string StudentNumber
    {
        get { return _studentNumber; }
        set { _studentNumber = value; }
    }

    public string LastName
    {
        get { return _lastName; }
        set { _lastName = value; }
    }

    public string FirstName
    {
        get { return _firtName; }
        set { _firtName = value; }
    }

    public List<Subject> Subjects
    {
        get { return …

我有XML,我正在反序列化,这是我的XML

<?xml version=\"1.0\" encoding=\"utf-16\"?>
<UserInfo xmlns:xsi='http://www.w3.org/2001/XMLSchema-instance' xmlns:xsd='http://www.w3.org/2001/XMLSchema'>  
<UserName>First_User</UserName>  
<Age>25</Age>  
</UserInfo>

我有这门课

namespace MyProject{
    [System.SerializableAttribute()]
    [System.Xml.Serialization.XmlRootAttribute(Namespace = "http:/MyProject.ServiceContracts/2006/11", IsNullable = false)]

    [DataContract]
    public class UserInfo
    {
       private string username;

        private string age;

        [DataMember]
        public string UserName
        {
            get
            {
                return this.username;
            }
            set
            {
                this.username = value;
            }
        }

           [DataMember]
        public string Age
        {
            get
            {
                return this.age;
            }
            set
            {
                this.age = value;
            }
        }

    }
    }

我这样做

     XmlSerializer xmlSerSale = new XmlSerializer(typeof(UserInfo));

                        StringReader stringReader = new StringReader(myXML);

                        info = …

我有这个XML,只是想知道如何转换成C#类？

<?xml version="1.0" encoding="utf-8"?>
<TextScrollerItems xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">

    <Item type="text" ID="234">
     <Text Color="Blue">
       Sample text...
     </Text>
    </Item>

    <Item type="image" ID="2456">
        <Image>
          clientLogo.png
        </Image>
    </Item>

    </TextScrollerItems>

我在外部提供了一个XML文档,我需要将其导入到我的应用程序中.该文件编写得很糟糕,但不是我真正能做的很多.

<?xml version="1.0" encoding="iso-8859-1"?>
<xml>
    <Items>
        <Property1 />
        <Property2 />
        ...
    </Items>
    <Items>
        <Property1 />
        <Property2 />
        ...
    </Items>
    ...
</xml>

我应该如何使用XmlSerializer这个？我使用什么类设置似乎并不重要,或者我放在XmlRoot(ElementName="xml")我的基类上它总是说它<xml xmlns=''>是意外的.

编辑:添加了我正在使用的C#代码

[XmlRoot(ElementName = "xml")]
public class Container
{
    public List<Items> Items { get; set; }
}

public class Items
{
    public short S1 { get; set; }
    public short S2 { get; set; }
    public short S3 { get; set; }
    public short S4 { get; set; }
    public short S5 …

使用C#，有没有一种方法可以轻松解析XML文件，以便将其用作对象？

XML 示例：

<Config>
    <Ui>
        <Colour>black</Colour>
        <Size>small</Size>
    </Ui>
    <Output>
        <Mode>smb</Mode>
        <Version>2</Version>
    </Output>
</Config>

然后参考我的应用程序中的参数

Config.Output.Mode

我尝试过这种方法 - How to Deserialize XML document

但当我尝试时

var cfg = new Config();
cfg.Load(@"config.xml");
Console.WriteLine(cfg.Output.Mode);

Visual Studio 指示 .Output.Mode 无效。

Config.Load 所在位置

Config.Output.Mode