Per*_*rry 2 c# xml xml-serialization
我在外部提供了一个XML文档,我需要将其导入到我的应用程序中.该文件编写得很糟糕,但不是我真正能做的很多.
<?xml version="1.0" encoding="iso-8859-1"?>
<xml>
<Items>
<Property1 />
<Property2 />
...
</Items>
<Items>
<Property1 />
<Property2 />
...
</Items>
...
</xml>
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我应该如何使用XmlSerializer这个?我使用什么类设置似乎并不重要,或者我放在XmlRoot(ElementName="xml")我的基类上它总是说它<xml xmlns=''>是意外的.
编辑:添加了我正在使用的C#代码
[XmlRoot(ElementName = "xml")]
public class Container
{
public List<Items> Items { get; set; }
}
public class Items
{
public short S1 { get; set; }
public short S2 { get; set; }
public short S3 { get; set; }
public short S4 { get; set; }
public short S5 { get; set; }
public short S6 { get; set; }
public short S7 { get; set; }
}
public class XMLImport
{
public Container Data{ get; private set; }
public static XMLImport DeSerializeFromFile(string fileName)
{
XMLImport import = new XMLImport();
XmlSerializer serializer = new XmlSerializer(typeof(Container));
using (StreamReader reader = new StreamReader(fileName))
import.Data = (Container)serializer.Deserialize(reader);
return import;
}
}
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假设您有一个Items到每个<Items>节点的类映射:
public class Items
{
public string Property1 { get; set; }
public string Property2 { get; set; }
}
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您可以反序列化您的列表Items:
var doc = XDocument.Parse(
@"<?xml version=""1.0"" encoding=""iso-8859-1""?>
<xml>
<Items>
<Property1 />
<Property2 />
</Items>
<Items>
<Property1 />
<Property2 />
</Items>
</xml>");
var serializer = new XmlSerializer(typeof(List<Items>), new XmlRootAttribute("xml"));
List<Items> list = (List<Items>)serializer.Deserialize(doc.CreateReader());
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