相关疑难解决方法(0)

是否可以断开lambda函数？如果"是",怎么样？

根据https://qt-project.org/wiki/New_Signal_Slot_Syntax我需要使用QMetaObject::Connection从QObject :: connect方法返回的,但是我如何将该对象传递给lambda函数？

伪代码示例:

QMetaObject::Connection conn = QObject::connect(m_sock, &QLocalSocket::readyRead, [this](){
    QObject::disconnect(conn); //<---- Won't work because conn isn't captured

    //do some stuff with sock, like sock->readAll();
}