相关疑难解决方法(0)

我正在尝试设置按钮的可见性,如下所示:

public Bundle setActivityState(Bundle bundle){
    startBtn = (Button) findViewById(R.id.startSensorsBtn);

    startBtn.setVisibility(
            getVisibilityState(bundle, PersistanceConstants.START_BTN_STATE)
    );          

    return bundle;
}

public int getVisibilityState(Bundle bundle, String keyName){
    if (bundle.getInt(keyName) == View.VISIBLE){
        return View.VISIBLE;
    } else if (bundle.getInt(keyName) == View.INVISIBLE){
        return View.INVISIBLE;
    } else if (bundle.getInt(keyName) == View.GONE){
        return View.GONE;
    }

    return 0;
}

但是我收到了错误:

Must be one of: View.VISIBLE, View.INVISIBLE, View.GONE less... (Ctrl+F1) 
Reports two types of problems:
- Supplying the wrong type of resource identifier. For example, when calling Resources.getString(int id), you should be …