无法动态设置setVisibility()参数

Question

我正在尝试设置按钮的可见性,如下所示:

public Bundle setActivityState(Bundle bundle){
    startBtn = (Button) findViewById(R.id.startSensorsBtn);

    startBtn.setVisibility(
            getVisibilityState(bundle, PersistanceConstants.START_BTN_STATE)
    );          

    return bundle;
}

public int getVisibilityState(Bundle bundle, String keyName){
    if (bundle.getInt(keyName) == View.VISIBLE){
        return View.VISIBLE;
    } else if (bundle.getInt(keyName) == View.INVISIBLE){
        return View.INVISIBLE;
    } else if (bundle.getInt(keyName) == View.GONE){
        return View.GONE;
    }

    return 0;
}

但是我收到了错误:

Must be one of: View.VISIBLE, View.INVISIBLE, View.GONE less... (Ctrl+F1) 
Reports two types of problems:
- Supplying the wrong type of resource identifier. For example, when calling Resources.getString(int id), you should be passing R.string.something, not R.drawable.something.
- Passing the wrong constant to a method which expects one of a specific set of constants. For example, when calling View#setLayoutDirection, the parameter must be android.view.View.LAYOUT_DIRECTION_LTR or android.view.View.LAYOUT_DIRECTION_RTL.

一边打电话

getVisibilityState(bundle, PersistanceConstants.START_BTN_STATE)

我不知道怎么解决这个问题.我知道它期待一组给定的值,但我所知道的只是传递int给它.这可以做什么？

Answer 1

当您知道自己在做什么时,可以在本地禁止此Android Studio检查

//noinspection ResourceType

例如,

//noinspection ResourceType
startBtn.setVisibility(bundle.getInt(PersistanceConstants.START_BTN_STATE));

Answer 2

派对有点晚了但是另一个解决方案如果你在代码中使用了很多这个并且你有一个方法返回那个int就是定义你自己的Visibility注释,所以像这样:

public class MyStuff {

    @IntDef({View.VISIBLE, View.INVISIBLE, View.GONE})
    @Retention(RetentionPolicy.SOURCE)
    public @interface Visibility {
    }

    public @Visibility int getVisibility() {
        return View.GONE;
    }
}

如果你这样做,那么AS将不再抱怨因为你正在返回一个正确的int def.