DGr*_*ham 0 python if-statement
我无法调整它,因为它只响应1到100之间的值.我知道它的简单,但通过搜索找不到任何东西.
while True:
Mynumber = raw_input('Enter number of random points')
if Mynumber == '0 < 100':
print 'number choosen'
Mynumber = int(Mynumber)
break
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Sil*_*Ray 12
if 1 <= my_number <= 100:
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或者,因为您从raw_input获取并且必须首先转换为int未知字符串:
try:
my_number = int(raw_number)
except ValueError:
print "%s not an integer value." % raw_number
else:
if 1 <= raw_number <= 100:
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虽然进一步分析,看起来你正在尝试:
base_prompt = 'Enter number of random points'
user_input = raw_input(base_prompt)
while True:
try:
input_number = int(user_input)
except ValueError:
user_input = raw_input('%s not an interger\n%s' % (user_input, base_prompt))
else:
if 1 <= input_number <= 100:
break
else:
user_input = raw_input('%d out of range (1 to 100)\n%s' % (input_number, base_prompt))
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