ProtoBuf-Net错误消息"源数据中的无效字段:0"

Question

我成功序列化了以下类的实例,但是当我在收到以下错误消息后尝试反序列化时:" Invalid field in source data: 0".

我不知道它是指什么,因为我发现下面的课程直截了当.我刚刚将protobuf-net版本更新为2.00.614(运行时版本:2.0.50727).

知道我是否可能忽视一些微不足道的事情？

[ProtoContract]
public class TimeSeriesProperties 
{
    [ProtoMember(1)]
    public string TimeSeriesName { get; private set; }
    [ProtoMember(2)]
    public string FileName { get; private set; }
    [ProtoMember(3)]
    public string TemplateName { get; private set; }
    [ProtoMember(4)]
    public int PacketLength { get; private set; }
    [ProtoMember(5)]
    public long FileSizeBytes { get; set; }
    [ProtoMember(6)]
    public long NumberRecords { get; set; }
    [ProtoMember(7)]
    public DateTime DateTimeStart { get; set; }
    [ProtoMember(8)]
    public DateTime DateTimeEnd { get; set; }

    public TimeSeriesProperties()
    {

    }

    public TimeSeriesProperties(string timeSeriesName, string fileName, string templateName, int PacketLength)
    {
        this.TimeSeriesName = timeSeriesName;
        this.FileName = fileName;
        this.TemplateName = templateName;
        this.PacketLength = PacketLength;
    }

}

public static byte[] Serialize_ProtoBuf<T>(T serializeThis)
    {
        using (var stream = new MemoryStream())
        {
            ProtoBuf.Serializer.Serialize<T>(stream, serializeThis);
            return stream.GetBuffer();
        }
    }

    public static T Deserialize_ProtoBuf<T>(byte[] byteArray)
    {
        using (var stream = new MemoryStream(byteArray))
        {
            return ProtoBuf.Serializer.Deserialize<T>(stream);
        }
    }

Answer 1

我见过这个最常见的原因就是GetBuffer()在a上使用不正确MemoryStream.当我添加评论时,这已经是我的预感,但你已经确认了:

using (var stream = new MemoryStream())
{
    ProtoBuf.Serializer.Serialize<T>(stream, serializeThis);
    return stream.GetBuffer();
}

GetBuffer返回超大的后备缓冲区.它最后有垃圾.这是完全正常使用GetBuffer,只要你还记录.Length,这是量的有效数据在那里.这可以避免额外分配潜在的大型阵列.但在您的情况下,可能会使用更简单的方法ToArray()来获取正确大小的缓冲区:

using (var stream = new MemoryStream())
{
    ProtoBuf.Serializer.Serialize<T>(stream, serializeThis);
    return stream.ToArray();
}