按标签和用户名筛选instagram api结果

Question

我想创建一个从某个标签中提取图像的应用程序,但只能从某个用户名中提取图像.例如:我希望显示#skullcandysnow图像,但只显示'skullcandy'帐户名称中的图像.

这是我拉标签的方式:

 $(function() {

 $.ajax({
        type: "GET",
        dataType: "jsonp",
        cache: false,
        url: "https://api.instagram.com/v1/tags/skullcandysnow/media/recent?client_id=d1685ded02da4c5eb2b08632f1256119&access_token=fce470c159274e2b9482976f93fd3435",
        success: function(data) {



            for (var i = 0; i < 10; i++) {

        $(".SC-IG").append("<img class='SC-instagram-image' src='" + data.data[i].images.low_resolution.url +"' /><div class='counts'><img src='images/skullcandyad_04.jpg'><h3 class='ig-likescount'>" + data.data[i].likes.count +"</h3><h3 class='ig-commentscount'>" + data.data[i].comments.count +"</h3></div> ");   


        }
       }

    });
});

您可以在此处查看我正在处理的内容:http: //yobeat.com/zz_testing/yobeatinstagramwidget_v3.html

谢谢!

Answer 1

查看该用户在其“find it out”网站上提供的代码，解决方案如下：

imgLimit = 1000;
// Grab all TAGS of choice
$.ajax({
    type: "GET",
    dataType: "jsonp",
    cache: false,
    url: "https://api.instagram.com/v1/tags/TAG_OF_CHOICE/media/recent?client_id=CLIENT_ID&access_token=ACCESS_TOKEN",
    success: function(data) { 
    // Loop through the data and only add the images that match a certain user ID
        for (var i = 0; i < imgLimit; i++) {
            var usertag = data.data[i].user.id;
            if (usertag === "USER_ID_OF_CHOICE") {
                // Add image to page
                addImage(data.data[i]);
            }
       }
    }
});