Eme*_*mer 4 graphics r wireframe lattice
以下代码使用晶格的线框功能绘制3个彩色平面.但是,我无法理解为什么图例不会通过设置颜色组而改变.我尝试手动完成,但我最终只更改了文本颜色.顺便问一下,有没有人也知道如何使表面透明70%?
library(lattice)
library(akima)
SurfaceData <- data.frame(
x=rep(seq(0,100,length.out=10),each=10,times=3),
y=rep(rep(seq(0,100,length.out=10),times=10),times=3),
z=c(rep(25,100),seq(30,70,length.out=100),seq(95,75,length.out=100)),
type=factor(rep(c("A","B","C"),each=100))
)
wireframe(z~x*y,data=SurfaceData,group=type,
col.groups=c("red","green","blue"),
scales = list(arrows=FALSE, col="black",font=10),
xlab = list("Variable X",rot=30),
ylab = list("Variable Y",rot=-30),
zlab = list("Variable Z",rot=90),
zlim = c(0,100),
#auto.key=TRUE,
auto.key=list(text=c("A","B","C"),col=c("red","green","blue"),lines=TRUE),
par.settings = list(axis.line = list(col = "transparent")),
)
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结果:

谢谢!
要改变线条的颜色,应更换auto.key同key和文本和线条提供值的列表.
wireframe(z~x*y,data=SurfaceData,group=type,
col.groups=c("red","green","blue"),
scales = list(arrows=FALSE, col="black",font=10),
xlab = list("Variable X",rot=30),
ylab = list("Variable Y",rot=-30),
zlab = list("Variable Z",rot=90),
zlim = c(0,100),
key=list(text=list(c("A","B","C"),col=c("red","green","blue")),
lines=list(lty=c(1,1,1),col=c("red","green","blue"))),
par.settings = list(axis.line = list(col = "transparent")),
)
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要使颜色透明,您可以使用功能rgb().在这里,我定义mycolors.trans了包含透明颜色和mycolors相同颜色但对于图例条目不透明的新变量.
mycolors.trans = rgb(c(255,0,0),
c(0,255,0),
c(0,0,255),alpha = 70,maxColorValue = 255)
mycolors = rgb(c(255,0,0),
c(0,255,0),
c(0,0,255),maxColorValue = 255)
wireframe(z~x*y,data=SurfaceData,group=type,
col.groups=mycolors.trans,
scales = list(arrows=FALSE, col="black",font=10),
xlab = list("Variable X",rot=30),
ylab = list("Variable Y",rot=-30),
zlab = list("Variable Z",rot=90),
zlim = c(0,100),
#auto.key=TRUE,
key=list(text=list(c("A","B","C"),col=mycolors),
lines=list(lty=c(1,1,1),col=mycolors)),
par.settings = list(axis.line = list(col = "transparent")),
)
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