rth*_*sen 1 java mysql prepared-statement
这失败了: db.prepareStatement("SELECT * FROM " + table + " WHERE " + column + " LIKE '?%'");
因为?未将其识别为值的占位符.我应该如何解决这个问题?
将通配符放在变量中,而不是在语句中,如:
stmt = db.prepareStatement("SELECT * FROM " + table + " WHERE " + column + " LIKE ?");
stmt.setString(1, "myterm%");
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