从C#中的复杂JSON结构中提取数据

Question

我有JSON数据,如下所示:

{
   "position":[
      {
         "top":[
            42,
            12
         ]
      },
      {
         "middle":[
            10,
            15
         ]
      },
      {
         "bottom":[
            5,
            201
         ]
      },
      {
         "axis":[
            {
               "X":[
                  901,
                  51,
                  67
               ]
            },
            {
               "Y":[
                  1474186,
                  561647
               ]
            },
            {
               "Z":[
                  911,
                  1296501
               ]
            },
            15,
            20
         ]
      }
   ],
   "validated":true,
   "metadata":{
      "uri":"/data/complex/",
      "session":[
         1818,
         14
      ],
      "private":false
   },
   "vists":0,
   "ok":true,
   "data":{
      "10":{
         "title":"Alpha",
         "author":"Justin X. Ample",
         "cover":"/f48hf58.tiff"
      },
      "901":{
         "title":"Tau",
         "author":"Felina Blank",
         "cover":"/45trthrref.tiff"
      }
   },
   "live":null
}

从这些数据我想显示如下列表:

Alpha, Justin X. Ample
Tau, Felina Blank

请注意,键(在我的示例中为10和901)是不可预测的.所以我想以某种方式创建一个表示"数据"结构的对象,并迭代它以获得每个条目的标题和作者.

使用基本的JSON结构,我成功完成了这样的事情(使用JSON.NET):

public class Foo
    {
        public int bar { get; set; }
        public string baz { get; set; }
        public string quxx { get; set; }
    }

...

// json = {"bar": 1, "baz":"two", "quxx":"three"}
var result = await JsonConvert.DeserializeObjectAsync<Foo>(json);

return result.baz // "two"

但我无法弄清楚我需要做些什么才能使它与复杂的结构一起工作.

Answer 1

var jObj = JsonConvert.DeserializeObject(json) as JObject;
var result = jObj["data"].Children()
                .Cast<JProperty>()
                .Select(x => new { 
                    Title = (string)x.Value["title"] ,
                    Author = (string)x.Value["author"],
                })
                .ToList();