如何以编程方式在另一个shapeDrawable中绘制较小的ShapeDrawable

Question

我试图在另一个圆圈内绘制一个较小的圆圈.这似乎很简单,但我遇到了麻烦,无法找到答案.我使用的代码是:

    ShapeDrawable biggerCircle= new ShapeDrawable( new OvalShape());
    biggerCircle.setIntrinsicHeight( 60 );
    biggerCircle.setIntrinsicWidth( 60);
    biggerCircle.setBounds(new Rect(0, 0, 60, 60));
    biggerCircle.getPaint().setColor(Color.BLUE);

    ShapeDrawable smallerCircle= new ShapeDrawable( new OvalShape());
    smallerCircle.setIntrinsicHeight( 10 );
    smallerCircle.setIntrinsicWidth( 10);
    smallerCircle.setBounds(new Rect(0, 0, 10, 10));
    smallerCircle.getPaint().setColor(Color.BLACK);
    smallerCircle.setPadding(50,50,50,50);

    LayerDrawable composite1 = new LayerDrawable(new Drawable[] biggerCircle,smallerCircle,});

但那不起作用,会发生的是,较小的圆圈会变得像较大的圆圈一样大.所以唯一显示的是黑色圆圈,大圆圈的大小.如果有人可以提供帮助,我会帮助你.提前致谢.

Answer 1

改变顺序,

Drawable[] d = {smallerCircle,biggerCircle};

LayerDrawable composite1 = new LayerDrawable(d);

试试这样

        ShapeDrawable biggerCircle= new ShapeDrawable( new OvalShape());
        biggerCircle.setIntrinsicHeight( 60 );
        biggerCircle.setIntrinsicWidth( 60);
        biggerCircle.setBounds(new Rect(0, 0, 60, 60));
        biggerCircle.getPaint().setColor(Color.BLUE);

        ShapeDrawable smallerCircle= new ShapeDrawable( new OvalShape());
        smallerCircle.setIntrinsicHeight( 10 );
        smallerCircle.setIntrinsicWidth( 10);
        smallerCircle.setBounds(new Rect(0, 0, 10, 10));
        smallerCircle.getPaint().setColor(Color.BLACK);
        smallerCircle.setPadding(50,50,50,50);
        Drawable[] d = {smallerCircle,biggerCircle};

        LayerDrawable composite1 = new LayerDrawable(d);

        btn.setBackgroundDrawable(composite1);