Fre*_*ind 14 groovy jsonbuilder
我们可以通过groovy的json builder生成一个对象类型的json:
def builder = new groovy.json.JsonBuilder()
def root = builder.people {
person {
firstName 'Guillame'
lastName 'Laforge'
// Named arguments are valid values for objects too
address(
city: 'Paris',
country: 'France',
zip: 12345,
)
married true
// a list of values
conferences 'JavaOne', 'Gr8conf'
}
}
def jsonStr = builder.toString()
Run Code Online (Sandbox Code Playgroud)
我喜欢这种类型的语法,但是如何构建一个数组类型的json?
例如
[
{"code": "111", "value":"222"},
{"code": "222", "value":"444"}
]
Run Code Online (Sandbox Code Playgroud)
我发现一些文件说我们应该使用JsonBuilder()构造函数:
def mydata = [ ["code": "111", "value":"222"],["code": "222", "value":"444"] ]
def builder = new groovy.json.JsonBuilder(mydata)
def jsonStr = builder.toString()
Run Code Online (Sandbox Code Playgroud)
但我更喜欢第一种语法.是否能够使用它生成数组类型的json?
你提出的语法看起来不太可能,因为我不相信它是有效的常规.一个封闭,如{"blah":"foo"}groovy没有意义,你将受到语法限制的限制.我认为你能做的最好的事情是以下内容:
def root = builder.call (
[
{
code "111"
value "222"
},
{code "222"; value "444"}, //note these are statements within a closure, so ';' separates instead of ',', and no ':' used
[code: "333", value:"555"], //map also allowed
[1,5,7] //as are nested lists
]
)
Run Code Online (Sandbox Code Playgroud)
| 归档时间: |
|
| 查看次数: |
12987 次 |
| 最近记录: |