使用C#(ASP.NET MVC)上传CSV文件

Spi*_*dey 4 asp.net-mvc

我有一个包含以下内容的CSV文件:

ProductName,EmployeeID,EmployeeName,ContactNo,Adddress
iPad,1233,Tom,89897898,34 Pitt st
iPad,1573,Jack,8978 9689,50 George st
iPad,1893,Peter,8878 8989,32 Martin st 
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以下代码将插入到一个表中。我想要实现的是插入2个表中:

产品表(父表)
ProductId(Pk),产品名称

员工表(子表)
EmployeeId(Pk),ProductId(fk),EmployeeName,ContactNo,地址

因此,我基本上需要先将记录插入CSV文件的“产品”表中,然后再插入“雇员”表中。

Controller.cs

[HttpPost]
public ActionResult Index(HttpPostedFileBase FileUpload)
{
    // Set up DataTable place holder 

    Guid ProductId= Guid.NewGuid();
    using (SqlConnection conn = new SqlConnection(connString))
    {
        conn.Open();

        using (SqlCommand cmd = new SqlCommand(
               "INSERT INTO Product VALUES(" + "@ReferralListID,  @ProductName)", conn))
        {
            //Note product name need to read from csv file
            cmd.Parameters.AddWithValue("@ProductId", ProductId);
            cmd.Parameters.AddWithValue("@ProductName", ProductName); 

            int rows = cmd.ExecuteNonQuery();

            //rows number of record got inserted
        }
    }

    DataTable dt = new DataTable();

    //check we have a file 
    if (FileUpload.ContentLength > 0)
    {
        //Workout our file path
        string fileName = Path.GetFileName(FileUpload.FileName);
        string path = Path.Combine(Server.MapPath("~/App_Data/uploads"), fileName);

        //Try and upload
        try
        {
            FileUpload.SaveAs(path);
            //Process the CSV file and capture the results to our DataTable place holder
            dt = ProcessCSV(path);

            //Process the DataTable and capture the results to our SQL Bulk copy
            ViewData["Feedback"] = ProcessBulkCopy(dt);
        }
        catch (Exception ex)
        {
            //Catch errors
            ViewData["Feedback"] = ex.Message;
        }
    }
    else
    {
        //Catch errors
        ViewData["Feedback"] = "Please select a file";
    }

    //Tidy up
    dt.Dispose();

    return View("Index", ViewData["Feedback"]);
}

/// <summary>
/// Process the file supplied and process the CSV to a dynamic datatable
/// </summary>
/// <param name="fileName">String</param>
/// <returns>DataTable</returns>
private static DataTable ProcessCSV(string fileName)
{
    //Set up our variables 
    string Feedback = string.Empty;
    string line = string.Empty;
    string[] strArray;  
    DataTable dt = new DataTable();
    DataRow row;

    // work out where we should split on comma, but not in a sentance
    Regex r = new Regex(",(?=(?:[^\"]*\"[^\"]*\")*(?![^\"]*\"))");

    //Set the filename in to our stream
    StreamReader sr = new StreamReader(fileName);

    //Read the first line and split the string at , with our regular express in to an array
    line = sr.ReadLine();
    strArray = r.Split(line);

    //For each item in the new split array, dynamically builds our Data columns. Save us having to worry about it.
    Array.ForEach(strArray, s => dt.Columns.Add(new DataColumn()));


    //Read each line in the CVS file until it's empty
    while ((line = sr.ReadLine()) != null)
    {
        row = dt.NewRow();

        //add our current value to our data row
        row.ItemArray = r.Split(line);
        dt.Rows.Add(row);
    }

    //Tidy Streameader up
    sr.Dispose();

    //return a the new DataTable
    return dt;


}

/// <summary>
/// Take the DataTable and using WriteToServer(DataTable) send it all to the database table "BulkImportDetails" in one go
/// </summary>
/// <param name="dt">DataTable</param>
/// <returns>String</returns>
private static String ProcessBulkCopy(DataTable dt)
{
    string Feedback = string.Empty;
    string connString = ConfigurationManager.ConnectionStrings["DataBaseConnectionString"].ConnectionString;

    //make our connection and dispose at the end    
    using(  SqlConnection conn = new SqlConnection(connString))
    {
        //make our command and dispose at the end
        using (var copy = new SqlBulkCopy(conn))
        {
            //Open our connection
            conn.Open();

            //Set target table and tell the number of rows
            copy.DestinationTableName = "Employee";
            copy.BatchSize = dt.Rows.Count;
            try
            {
                //Send it to the server
                copy.WriteToServer(dt);
                Feedback = "Upload complete";
            }
            catch (Exception ex)
            {
                Feedback = ex.Message;
            }
        }
    }

    return Feedback;
}
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View.aspx

<asp:Content ID="Content1" ContentPlaceHolderID="TitleContent" runat="server">
    Home Page
</asp:Content>

<asp:Content ID="Content2" ContentPlaceHolderID="MainContent" runat="server">

    <h2>CSV Bulk Upload</h2> 

    <% using (Html.BeginForm("","",FormMethod.Post, new {enctype="multipart/form-data"})){ %>

        <input type="file" name="FileUpload" />
        <input type="submit" name="Submit" id="Submit" value="Upload" />
    <% } %>

    <p><%= Html.Encode(ViewData["Feedback"]) %></p> 
</asp:Content>
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储存程序

USE [BULkDatabase]
GO


SET ANSI_NULLS ON
GO

SET QUOTED_IDENTIFIER OFF
GO



CREATE PROCEDURE [dbo].[InsertProdutInfo] 
(
   @ProductName varchar (50),  
   @EmployeeName varchar (50),
   @EmployeeAddress varchar (50)
)

AS


BEGIN TRAN

   update [dbo.Product] 
   set    [ProductName] = @ProductName
   where  [ProductName] = @ProductName;

   -- get product id
   select ProductId = [ProductId] 
   from   [dbo.Product]
   where  [ProductName] = @ProductName;  

   if @@rowcount = 0
   BEGIN TRAN

      DECLARE @ProductId uniqueidentifier
      -- there's no such product, let's create it
      insert into [dbo.Product]
      values (NEWID(),@ProductName);

      select @ProductId = SCOPE_IDENTITY()
   end

   -- now that we know we have added the product and have the id, let's add the rest
   insert into [dbo.Employees]
   values (NEWID(), @EmployeeName, @EmployeeAddress, @ProductId);

COMMIT TRAN
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bal*_*dre 7

首先,您应该将Controller与数据库代码分离,只需简单地创建一个新的Class项目并在其中托管所有数据库访问权限,这样您就可以在Controller中进行如下操作:

[HttpPost]
public ActionResult UploadFile(HttpPostedFileBase FileUpload)
{
    if (FileUpload.ContentLength > 0) {
        // there's a file that needs our attention
        var success = db.UploadProductFile(FileUpload);

        // was everything ok?
        if (success)
            return View("UploadSuccess");
        else
            return View("UploadFail");
    }

    return RedirectToAction("Index", new { error = "Please upload a file..." });
}

public ActionResult Index(string error)
{
    ...
}
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通过这种方式,控制器并不真正关心你怎么用上传的文件做因为它不是Controller关心知道这样的事情,它必须知道它需要委派工作和处理结果的任务,就是这样。

请注意,调用了action方法UploadFile,没有调用Index。避免执行相同的操作,以避免在用户刷新页面时再次发布它,这不是一个好习惯。

我还建议您使用ADO.NET实体模型,ASP.NET网站中也有很多视频,这将极大地帮助您以更简单,更干净的方式使用数据库。

回到您的问题...在数据库类中,该方法UploadProductFile应类似于以下内容,并假设您要处理的记录不超过200条,最好使用内存来处理文件而不是花时间保存并再次阅读(有关更多信息,您应该像以前一样保存并处理文件):

private bool UploadProductFile(HttpPostedFileBase FileUpload)
{
    // get the file stream in a readable way
    StreamReader reader = new StreamReader(FileUpload.InputStream);

    // get a DataTable representing the passed string
    System.Data.DataTable dt = ProcessCSV(reader.ReadToEnd()); 

    // for each row, compose the statement
    bool success = true;
    foreach (System.Data.DataRow row in dt.Rows)
        success = db.InsertProdutInfo(row);

    return success;
}
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该方法InsertProdutInfo将触发类似于以下内容的存储过程

declare @product_key int

begin tran

   update [tbl_products] 
   set    [name] = @product_name, [last_update] = getdate()
   where  [name] = @product_name;

   -- get product id
   select @product_key = [id] 
   from   [tbl_products]
   where  [name] = @product_name;  

   if @@rowcount = 0
   begin
      -- there's no such product, let's create it
      insert into [tbl_products] (name, last_update)
      values (@product_name, getdate());

      select @product_key = SCOPE_IDENTITY()
   end

   -- now that we know we have added the product and have the id, let's add the rest
   insert into [tbl_Employees] (id, product_id, name, contact, address)
   values (@employee_id, @product_key, @employee_name,
           @employee_contact, @employee_address);

commit tran
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这样,您将拥有所需的一切。

  • 我想像一下您遇到的问题? (10认同)