rad*_*ins 10 php mysqli while-loop
我是mysqli的新手,并且遇到了使用mysqli循环结果的问题.不幸的是,我只得到了一个结果.当我将查询放入phpMyAdmin时,它会得到三个结果.我相信相关的代码在这里,我只是称错了:
$connection = new mysqli($host, $databaseUsername, $databasePassword, $database);
if ($connection->connect_errno > 0) {
die ('Unable to connect to database [' . $connection->connect_error . ']');
}
$sql = "SELECT clientId, studentFirstName, studentLastName
FROM clients
WHERE (studentEmail = '$postEmail') OR (parentEmail = '$postEmail');";
if (!$result = $connection->query($sql)) {
die ('There was an error running query[' . $connection->error . ']');
}
echo '<select class = "toolbarDropdown" id = "toolbarDropdown-MultipleAccounts">';
while ($row = $result->fetch_array()) {
echo '<option value="'.$row["clientId"].'">'.$row["studentFirstName"].' '.$row["studentLastName"].'</option>';
}
echo '</select>';
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hek*_*mgl 15
您在HTML中缺少结束"at option ="值< -
注意
$row = $result->fetch_array()
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可以替换为
$row = $result->fetch_assoc()
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这样做,您获取的每个记录的数组将占用一半的大小.