尝试使用 PHP DOM 替换节点文本而不更改子节点

Question

我正在尝试使用 dom 对象来简化词汇表工具提示的实现。我需要做的是替换段落中的文本元素，但不是替换可能嵌入段落中的锚标记。

$html = '<p>Replace this tag not this <a href="#">tag</a></p>';
$document = new DOMDocument();
$document->loadHTML($html);
$document->preserveWhiteSpace = false;
$document->validateOnParse = true;

$nodes = $document->getElementByTagName("p");
foreach ($nodes as $node) {
  $node->nodeValue = str_replace("tag","element",$node->nodeValue);
}
echo $document->saveHTML();

我得到：

'...<p>Replace this element not this element</p>...'

我想：

'...<p>Replace this element not this <a href="#">tag</a></p>...'

如何实现这一点，以便仅更改父节点文本而不更改子节点（标签）？

Answer 1

尝试这个：

$html = '<p>Replace this tag not this <a href="#">tag</a></p>';
$document = new DOMDocument();
$document->loadHTML($html);
$document->preserveWhiteSpace = false;
$document->validateOnParse = true;

$nodes = $document->getElementsByTagName("p");

foreach ($nodes as $node) {
    while( $node->hasChildNodes() ) {
        $node = $node->childNodes->item(0);
    }
    $node->nodeValue = str_replace("tag","element",$node->nodeValue);
}
echo $document->saveHTML();

希望这可以帮助。

更新 要回答@paul 在下面的评论中的问题，您可以创建

$html = '<p>Replace this tag not this <a href="#">tag</a></p>';
$document = new DOMDocument();
$document->loadHTML($html);
$document->preserveWhiteSpace = false;
$document->validateOnParse = true;

$nodes = $document->getElementsByTagName("p");

//create the element which should replace the text in the original string
$elem = $document->createElement( 'dfn', 'tag' );
$attr = $document->createAttribute('title');
$attr->value = 'element';
$elem->appendChild( $attr );

foreach ($nodes as $node) {
    while( $node->hasChildNodes() ) {
        $node = $node->childNodes->item(0);
    }
    //dump the new string here, which replaces the source string
    $node->nodeValue = str_replace("tag",$document->saveHTML($elem),$node->nodeValue);
}
echo $document->saveHTML();