emp*_*set 11 c string httpresponse libcurl
我有功课,我需要以某种方式比较两个HTTP响应.我在C上写它,我使用libcurl使事情变得更容易.我正在调用使用libcurl来执行HTTP请求和来自另一个函数的响应的函数,我想将HTTP响应作为一个返回char *.这是我到目前为止的代码(它崩溃):
#include <stdio.h>
#include <curl/curl.h>
#include <string.h>
size_t write_data(void *ptr, size_t size, size_t nmemb, void *stream) {
size_t written;
written = fwrite(ptr, size, nmemb, stream);
return written;
}
char *handle_url(void) {
CURL *curl;
char *fp;
CURLcode res;
char *url = "http://www.yahoo.com";
curl = curl_easy_init();
if (curl) {
curl_easy_setopt(curl, CURLOPT_URL, url);
curl_easy_setopt(curl, CURLOPT_WRITEFUNCTION, write_data);
curl_easy_setopt(curl, CURLOPT_WRITEDATA, fp);
res = curl_easy_perform(curl);
if(res != CURLE_OK)
fprintf(stderr, "curl_easy_perform() failed: %s\n", curl_easy_strerror(res));
curl_easy_cleanup(curl);
//printf("\n%s", fp);
}
return fp;
}
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这个解决方案C libcurl得到输出到一个字符串的工作,但不是在我的情况下因为我只想将字符串返回给调用函数.
有任何想法吗?
mpo*_*llo 20
为你修好了.您需要处理write_data()多次调用函数的情况,并传递正确的参数.您还需要跟踪您所拥有的结构的大小,以便分配足够的内存.
我在函数中进行了调试printf,write_data以帮助您了解它的工作原理.
#include <stdio.h>
#include <curl/curl.h>
#include <string.h>
#include <stdlib.h>
struct url_data {
size_t size;
char* data;
};
size_t write_data(void *ptr, size_t size, size_t nmemb, struct url_data *data) {
size_t index = data->size;
size_t n = (size * nmemb);
char* tmp;
data->size += (size * nmemb);
#ifdef DEBUG
fprintf(stderr, "data at %p size=%ld nmemb=%ld\n", ptr, size, nmemb);
#endif
tmp = realloc(data->data, data->size + 1); /* +1 for '\0' */
if(tmp) {
data->data = tmp;
} else {
if(data->data) {
free(data->data);
}
fprintf(stderr, "Failed to allocate memory.\n");
return 0;
}
memcpy((data->data + index), ptr, n);
data->data[data->size] = '\0';
return size * nmemb;
}
char *handle_url(char* url) {
CURL *curl;
struct url_data data;
data.size = 0;
data.data = malloc(4096); /* reasonable size initial buffer */
if(NULL == data.data) {
fprintf(stderr, "Failed to allocate memory.\n");
return NULL;
}
data.data[0] = '\0';
CURLcode res;
curl = curl_easy_init();
if (curl) {
curl_easy_setopt(curl, CURLOPT_URL, url);
curl_easy_setopt(curl, CURLOPT_WRITEFUNCTION, write_data);
curl_easy_setopt(curl, CURLOPT_WRITEDATA, &data);
res = curl_easy_perform(curl);
if(res != CURLE_OK) {
fprintf(stderr, "curl_easy_perform() failed: %s\n",
curl_easy_strerror(res));
}
curl_easy_cleanup(curl);
}
return data.data;
}
int main(int argc, char* argv[]) {
char* data;
if(argc < 2) {
fprintf(stderr, "Must provide URL to fetch.\n");
return 1;
}
data = handle_url(argv[1]);
if(data) {
printf("%s\n", data);
free(data);
}
return 0;
}
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注意:编译gcc -o test test.c -lcurl(假设你粘贴test.c).使用gcc -o test test.c -lcurl -DDEBUG查看测试printf()呼叫.
免责声明:这是一个丑陋,快速和肮脏的代码.可能有错误.请在此处查看更强大,更好的评论示例.