C libcurl将输出转换为字符串

Question

我想将此curl函数的结果存储在变量中,我该怎么办？

#include <stdio.h>
#include <curl/curl.h>

int main(void)
{
  CURL *curl;
  CURLcode res;

  curl = curl_easy_init();
  if(curl) {
    curl_easy_setopt(curl, CURLOPT_URL, "curl.haxx.se");
    res = curl_easy_perform(curl);

    /* always cleanup */
    curl_easy_cleanup(curl);
  }
  return 0;
}

谢谢,我这样解决了:

#include <stdio.h>
#include <stdlib.h>
#include <curl/curl.h>

function_pt(void *ptr, size_t size, size_t nmemb, void *stream){
    printf("%d", atoi(ptr));
}

int main(void)
{
  CURL *curl;
  curl = curl_easy_init();
  if(curl) {
    curl_easy_setopt(curl, CURLOPT_URL, "curl.haxx.se");
    curl_easy_setopt(curl, CURLOPT_WRITEFUNCTION, function_pt);
    curl_easy_perform(curl);
    curl_easy_cleanup(curl);
  }
  system("pause");
  return 0;
}

Answer 1

您可以设置回调函数以使用接收传入的数据块 curl_easy_setopt(curl, CURLOPT_WRITEFUNCTION, myfunc);

回调将采用您可以使用的用户定义参数 curl_easy_setopt(curl, CURLOPT_WRITEDATA, p)

这是一段代码,它将缓冲区传递struct string {*ptr; len}给回调函数,并使用realloc()在每次调用时增加缓冲区.

#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <curl/curl.h>

struct string {
  char *ptr;
  size_t len;
};

void init_string(struct string *s) {
  s->len = 0;
  s->ptr = malloc(s->len+1);
  if (s->ptr == NULL) {
    fprintf(stderr, "malloc() failed\n");
    exit(EXIT_FAILURE);
  }
  s->ptr[0] = '\0';
}

size_t writefunc(void *ptr, size_t size, size_t nmemb, struct string *s)
{
  size_t new_len = s->len + size*nmemb;
  s->ptr = realloc(s->ptr, new_len+1);
  if (s->ptr == NULL) {
    fprintf(stderr, "realloc() failed\n");
    exit(EXIT_FAILURE);
  }
  memcpy(s->ptr+s->len, ptr, size*nmemb);
  s->ptr[new_len] = '\0';
  s->len = new_len;

  return size*nmemb;
}

int main(void)
{
  CURL *curl;
  CURLcode res;

  curl = curl_easy_init();
  if(curl) {
    struct string s;
    init_string(&s);

    curl_easy_setopt(curl, CURLOPT_URL, "curl.haxx.se");
    curl_easy_setopt(curl, CURLOPT_WRITEFUNCTION, writefunc);
    curl_easy_setopt(curl, CURLOPT_WRITEDATA, &s);
    res = curl_easy_perform(curl);

    printf("%s\n", s.ptr);
    free(s.ptr);

    /* always cleanup */
    curl_easy_cleanup(curl);
  }
  return 0;
}

Answer 2

以下答案是C++的方法std::string,而不是以null结尾的字符串.它仍然使用回调函数(没有办法绕过它),但也使用try/catch处理分配错误.

#include <iostream>
#include <string>
#include <curl/curl.h>

size_t CurlWrite_CallbackFunc_StdString(void *contents, size_t size, size_t nmemb, std::string *s)
{
    size_t newLength = size*nmemb;
    try
    {
        s->append((char*)contents, newLength);
    }
    catch(std::bad_alloc &e)
    {
        //handle memory problem
        return 0;
    }
    return newLength;
}
int main()
{
    CURL *curl;
    CURLcode res;

    curl_global_init(CURL_GLOBAL_DEFAULT);

    curl = curl_easy_init();
    std::string s;
    if(curl)
    {

        curl_easy_setopt(curl, CURLOPT_URL, "curl.haxx.se");

        curl_easy_setopt(curl, CURLOPT_SSL_VERIFYPEER, 0L); //only for https
        curl_easy_setopt(curl, CURLOPT_SSL_VERIFYHOST, 0L); //only for https
        curl_easy_setopt(curl, CURLOPT_WRITEFUNCTION, CurlWrite_CallbackFunc_StdString);
        curl_easy_setopt(curl, CURLOPT_WRITEDATA, &s);
        curl_easy_setopt (curl, CURLOPT_VERBOSE, 1L); //remove this to disable verbose output


        /* Perform the request, res will get the return code */
        res = curl_easy_perform(curl);
        /* Check for errors */
        if(res != CURLE_OK)
        {
            fprintf(stderr, "curl_easy_perform() failed: %s\n",
                    curl_easy_strerror(res));
        }

        /* always cleanup */
        curl_easy_cleanup(curl);
    }

    std::cout<<s<<std::endl;

    std::cout<< "Program finished!" << std::endl;
}

Answer 3

从这里阅读手册:http://curl.haxx.se/libcurl/c/curl_easy_setopt.html我认为您需要多次调用CURL_SETOPT,第一个是您要处理的URL,第二个是:

curl_easy_setopt(curl, CURLOPT_WRITEFUNCTION, function_ptr);

其中function_ptr匹配此签名:

size_t function( void *ptr, size_t size, size_t nmemb, void *stream)

这里发生的是你表示一个回调函数,当libcurl有一些输出要从你调用的任何传输中写入时,它将调用它.您可以让它自动写入文件,或者将指针传递给将处理输出本身的函数.使用此功能,您应该能够将各种输出字符串组合成一个部分,然后在程序中使用它们.

我不确定您可能需要设置哪些其他选项/还有什么会影响您希望应用程序的行为,因此请仔细查看该页面.

Answer 4

这是alex-jasmin接受的答案的 C++ 风格

#include <iostream>
#include <string>
#include <curl/curl.h>

size_t writefunc(void *ptr, size_t size, size_t nmemb, std::string *s) 
{
  s->append(static_cast<char *>(ptr), size*nmemb);
  return size*nmemb;
}

int main(void)
{
  CURL *curl = curl_easy_init();
  if (curl)
  {
    std::string s;

    curl_easy_setopt(curl, CURLOPT_URL, "curl.haxx.se");
    curl_easy_setopt(curl, CURLOPT_WRITEFUNCTION, writefunc);
    curl_easy_setopt(curl, CURLOPT_WRITEDATA, &s);

    CURLcode res = curl_easy_perform(curl);

    std::cout << s << std::endl;

    /* always cleanup */
    curl_easy_cleanup(curl);
  }
  return 0;
}