exc_bad_access(code = 1,address = 0x2012

Ale*_*dro 1 cocoa-touch objective-c ios

我收到此错误:

exc_bad_access (code=1, address=0x2012 
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当我尝试以这种方式从单身人士那里收到一个值时:

Draggable* sharedSingleton = [Draggable sharedManagerDraggable];
NSLog(@"%@", sharedSingleton.namePassedToDraggable);
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上面的代码放在UIImageView类型的Draggable.m中,它还具有:

+ (Draggable *)sharedManagerDraggable
{
static Draggable *sharedManagerDraggable = nil;
static dispatch_once_t onceToken;
dispatch_once(&onceToken, ^{
    sharedManagerDraggable = [[Draggable alloc] init];
});
return sharedManagerDraggable;
}
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我以这种方式为namePassedToDraggable赋值(从视图controller.m):

#import Draggable.h

Draggable* sharedSingleton = [Draggable sharedManagerDraggable];
    sharedSingleton.namePassedToDraggable = txt.text;
        NSLog(@"%@", sharedSingleton.namePassedToDraggable);
    dragger.tag = img.tag;
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在Draggable.h我有:

+ (Draggable *) sharedManagerDraggable;

@property (nonatomic, assign) NSString* namePassedToDraggable;
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为什么我会收到导致应用崩溃的错误?我在其他viewcontorllers中使用相同的方法,它工作得很好!

小智 11

@property (nonatomic, assign) NSString* namePassedToDraggable;
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应该

@property (nonatomic, strong) NSString* namePassedToDraggable;
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如果属性不是strong,则不会保留它,并且在您分配它的函数范围的末尾释放它.