Spring Transaction中是否需要异常处理？

Question

我对使用Transaction进行异常处理有疑问.为了清楚说明我的问题,我想展示我的配置:

<bean id="transactionManager" class="org.springframework.orm.hibernate4.HibernateTransactionManager">
    <property name="sessionFactory" ref="sessionFactory" />
</bean>

<tx:annotation-driven transaction-manager="transactionManager" />

<bean id="transactionInterceptor" abstract="true" class="org.springframework.transaction.interceptor.TransactionProxyFactoryBean">
    <property name="transactionManager" ref="transactionManager" />
    <property name="transactionAttributeSource">
        <bean class="org.springframework.transaction.annotation.AnnotationTransactionAttributeSource" />
    </property>
</bean>

<bean id="baseService" abstract="true">
    <property name="daoProvider" ref="daoProvider" />
</bean>

<bean id="customerService" parent="transactionInterceptor">
    <property name="target">
        <bean class="com.edfx.adb.service.CustomerService" parent="baseService" />
    </property>
</bean>

<bean id="daoProvider" class="com.edfx.adb.dao.provider.DaoProvider">   
    <property name="customerDao" ref="customerDao" />
</bean>

<bean id="customerDao" class="com.edfx.adb.dao.CustomerDao">
    <constructor-arg value="#{T(com.edfx.adb.persist.entity.Customer)}" />
    <property name="sessionFactory" ref="sessionFactory" />
</bean>

活动事务类是:

@Transactional
public class CustomerService extends BaseService implements ICustomerService {

    @Transactional(readOnly = true)
    public Customer getCustomerById(String id) {
        return getDaoProvider().getCustomerDao().getCustomerById(id);
    }

    @Transactional(readOnly = false, propagation = Propagation.REQUIRED, rollbackFor = { Throwable.class })
    public void addNewCustomer(CustomerDTO customerDTO) {
        Customer customer = new Customer();

        customer.setCustomerId(customerDTO.getCustomerId());
        customer.setCustomerName(customerDTO.getCustomerName());
        customer.setActive(customerDTO.isActive());

        getDaoProvider().getCustomerDao().save(customer);
    }
}

我的疑惑在于方法addNewCustomer.我已经定了rollbackFor = { Throwable.class }.

它是如何工作的？

我还需要显式处理异常,如:

@Transactional(readOnly = false, propagation = Propagation.REQUIRED, rollbackFor = { Throwable.class })
public boolean addNewCustomer(CustomerDTO customerDTO) {
    Customer customer = new Customer();

    customer.setCustomerId(customerDTO.getCustomerId());
    customer.setCustomerName(customerDTO.getCustomerName());
    customer.setActive(customerDTO.isActive());

    try {
        getDaoProvider().getCustomerDao().save(customer);
    } catch (Throwable throwable) {
        return false;
    }

    return true;
}

强制我通过删除customer表中的列来创建异常,但是try-catch块中没有捕获异常,而是我可以从我调用该addNewCustomer方法的托管bean中捕获该异常.

Answer 1

这是Spring文档的摘录

在其默认配置中,Spring Framework的事务基础结构代码仅在运行时未经检查的异常情况下标记用于回滚的事务; 也就是说,抛出的异常是RuntimeException的实例或子类.(错误也将 - 默认情况下 - 导致回滚).从事务方法抛出的已检查异常不会导致在默认配置中回滚.

你设置rollbackFor = Throwable.class,现在Spring会回滚任何Exception/Error.默认情况下,无论我们是否喜欢,Spring将仅针对RuintimeException进行回滚,否则进行提交

Answer 2

Spring框架只抛出RuntimeExceptions,从技术上讲,你永远不必捕获任何异常.