JIRA 问题密钥正则表达式

Ada*_*itt 0 c# regex

我想要一个正则表达式来匹配并从这句话中提取 BUG-123:

some junk here BUG-123 My bug description goes here
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谢谢

Ani*_*dha 5

您可以使用BUG-(\d+)

所以它会是

List<string> bugNos=Regex.Matches(yourString,@"BUG-(\d+)",RegexOptions.IgnoreCase)
                       .Cast<Match>()
                       .Select(x=>x.Value).ToList();
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