我想要一个正则表达式来匹配并从这句话中提取 BUG-123:
some junk here BUG-123 My bug description goes here
Run Code Online (Sandbox Code Playgroud)
谢谢
您可以使用BUG-(\d+)
所以它会是
List<string> bugNos=Regex.Matches(yourString,@"BUG-(\d+)",RegexOptions.IgnoreCase)
.Cast<Match>()
.Select(x=>x.Value).ToList();
Run Code Online (Sandbox Code Playgroud)