tot*_*oto 7 java servlets file-upload http multipartform-data
我在Android中有一个客户端应用程序,HttpURLConnection用于将文件发送到服务器.服务器使用Apache Commons FileUpload API来解析表单数据值.
该HttpURLConnection发送该请求:
-----------------------------4912995119421
Content-Disposition: form-data; name="deviceid"
9428103
-----------------------------4912995119421
Content-Disposition: form-data; name="countryid"
598
-----------------------------4912995119421
Content-Disposition: form-data; name="number"
98621360
-----------------------------4912995119421
Content-Disposition: form-data; name="file"; filename="2012-12-08 17.42.18.jpg"
Content-Type: image/jpeg
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-----------------------------4912995119421--
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服务器代码:
String contentType = request.getContentType();
if ((contentType.indexOf("multipart/form-data") == -1)) {
response.setStatus(HttpServletResponse.SC_NOT_FOUND);
return;
}
long maxFileSize = (2 * 1024 * 1024);
int maxMemSize = (2 * 1024 * 1024);
DiskFileItemFactory factory = new DiskFileItemFactory();
// maximum size that will be stored in memory
factory.setSizeThreshold(maxMemSize);
// Create a new file upload handler
ServletFileUpload upload = new ServletFileUpload(factory);
// maximum file size to be uploaded.
upload.setSizeMax(maxFileSize);
List fileItems = upload.parseRequest(request);
Iterator i = fileItems.iterator();
//leo primero todas las variables.
int deviceID = 0;
int countryID = 0;
String phoneNumber = "";
while (i.hasNext()) {
FileItem fi = (FileItem) i.next();
if (fi.isFormField()) {
String variable = fi.getFieldName();
if (variable.equals("deviceid")) {
deviceID = Integer.parseInt(fi.getString());
} else if (variable.equals("countryid")) {
countryID = Integer.parseInt(fi.getString());
} else if (variable.equals("number")) {
phoneNumber = String.valueOf(Long.parseLong(fi.getString()));
}
}
}
if (deviceID == 0 || countryID == 0 || phoneNumber.equals("")) {
response.setStatus(HttpServletResponse.SC_NOT_FOUND);
return;
}
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问题就在于此List fileItems = upload.parseRequest(request);.返回的列表为空,我无法获取表单数据值.
Bal*_*usC 27
如果您已经(隐式)预先解析了请求主体,那么它将是空的.HTTP请求主体只能被读取/解析一次(因为客户端只发送一次并且不会多次发送它).
在将请求提交给Commons FileUpload 之前调用以下任何方法时,将隐式读取/解析请求体:
request.getParameter();
request.getParameterMap();
request.getParameterNames();
request.getParameterValues();
request.getReader();
request.getInputStream();
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您需要确保事先不要调用任何这些方法(还要检查所有servlet过滤器以确保).
如果你已经确定你没有这样做,那么唯一的其他可能原因是不正确的边界标题和/或使用不正确的换行符(它实际上是CR + LF,因此不是单独的LF).您可以在" 使用java.net.URLConnection"的底部找到一个具体而恰当的示例来触发和处理HTTP请求,在"上载文件"部分下.
如果使用spring,检查是否有<bean id="multipartResolver" class="org.springframework.web.multipart.commons.CommonsMultipartResolver" />in xml文件。有一个功能
protected HttpServletRequest checkMultipart(HttpServletRequest request) throws MultipartException {
if (this.multipartResolver != null && this.multipartResolver.isMultipart(request)) {
if (request instanceof MultipartHttpServletRequest) {
logger.debug("Request is already a MultipartHttpServletRequest - if not in a forward, " +
"this typically results from an additional MultipartFilter in web.xml");
}
else {
return this.multipartResolver.resolveMultipart(request);
}
}
// If not returned before: return original request.
return request;
}
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“吃”多部分项目。它会导致三个小时的疼痛。
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