代码:
Decimal kilometro = Decimal.TryParse(myRow[0].ToString(), out decimal 0);
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有些论点无效吗?
Ode*_*ded 28
out decimal 0 不是有效参数 - 0不是有效的变量名.
decimal output;
kilometro = decimal.TryParse(myRow[0].ToString(), out output);
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顺便说一句,返回值将是bool- 从变量的名称,您的代码应该是:
if(decimal.TryParse(myRow[0].ToString(), out kilometro))
{
// success - can use kilometro
}
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既然你想要回归kilometro,你可以这样做:
decimal kilometro = 0.0; // Not strictly required, as the default value is 0.0
decimal.TryParse(myRow[0].ToString(), out kilometro);
return kilometro;
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好吧,decimal.TryParse返回一个bool类型 - 所以你需要做一些类似的事情:
Decimal kilometro;
// if .TryParse is successful - you'll have the value in "kilometro"
if (!Decimal.TryParse(myRow[0].ToString(), out kilometro)
{
// if .TryParse fails - set the value for "kilometro" to 0.0
kilometro = 0.0m;
}
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