我想用输入表单更新MySQL数据库,本质上是一个用户可以更新/更改其信息的设置页面.使用下面的代码,底部的echo运行,我没有收到任何错误,但数据库没有更新.我在我的本地计算机和服务器上测试了它,但它也没有用,但我不确定它与它有什么关系.$_SESSION['yourName']用户登录时已设置,因此它将等于数据库中的当前值.我知道这里有很多sql注入漏洞,但这只是一个概念验证代码,还没有准备好上线.我尝试在phpMyAdmin中运行查询,它运行正常.
PHP
if(isset($_POST['name']) || isset($_POST['password']) || isset($_POST['location']) || isset($_POST['img'])) {
//put this in an external file for a little extra security
$username = "my_username";
$password = "my_password";
$database = "database_name";
$con = mysql_connect('localhost',$username,$password);
if (!$con) {
die('Oh poop.... Could not connect: ' . mysql_error());
}
//print item from database
mysql_select_db($database, $con);
if(isset($_POST['name'])) {
$query = 'UPDATE users SET username=' . $_POST['name'] . 'WHERE username=' . $_SESSION['yourName'];
mysql_query($query);
$_SESSION['yourName'] = $_POST['name'];
}
if(isset($_POST['password'])) {
$query = 'UPDATE users SET password=' . $_POST['password'] . 'WHERE username=' . $_SESSION['yourName'];
mysql_query($query);
}
if(isset($_POST['location'])) {
$query = 'UPDATE users SET location=' . $_POST['location'] . 'WHERE username=' . $_SESSION['yourName'];
mysql_query($query);
$_SESSION['location'] = $_POST['location'];
}
if(isset($_POST['img'])) {
$query = 'UPDATE users SET img=' . $_POST['img'] . 'WHERE username=' . $_SESSION['yourName'];
mysql_query($query);
$_SESSION['img'] = $_POST['img'];
}
echo '<script type="text/javascript">alert("changes saved")</script>';
}
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HTML
<form method="post">
new name: <input type="text" name="name" /><br />
new password: <input type="text" name="password" /><br />
new location: <input type="text" name="location" /><br />
new img: <input type="text" name="img" /><br />
<input type='submit' name='save' value='save' />
<input type='submit' name='logout' value='logout' />
</form>
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尝试使用双引号而不是单引号修改您的php语句.
$query = "UPDATE users SET username='" . $_POST['name'] . "' WHERE username= '" . $_SESSION['yourName'] . "'";
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但上面的查询容易受到影响SQL Injection,请阅读下面的文章,
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