jak*_*kob 5 mysql ebean playframework-2.0
我正在用Ebean构建一个Play2应用程序.我创建了一个服务类,其中包含一个通过id列表获取场地的方法:
public static List<Venue> getVenuesForIds(List<Long> list){
ArrayList<Venue> venues = new ArrayList<Venue>();
String sql = "select c.id, c.name from Company c where in (:ids)";
List<SqlRow> sqlRows =
Ebean.createSqlQuery(sql).setParameter("ids", list).findList();
for(SqlRow row : sqlRows) {
venues.add(new Venue(row.getLong("id"), row.getString("name")));
}
return venues;
}
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但是我得到了:
[PersistenceException: Query threw SQLException:You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'in (201639091,201637666)' at line 1 Query was: select c.id, c.name from Company c where in (?,?) ]
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我已阅读http://www.avaje.org/ebean/introquery.html,但可能错过了正确的语法.我想在原始sql中执行此操作.我错过了什么?
您的要求似乎不正确。
关于什么 :
"select c.id, c.name from Company c where c.id in (:ids)";
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