Java泛型:将整数与双精度进行比较

Question

任何人都可以帮助我使用泛型比较Integer和Double吗？

这就是我所拥有的:

public static <T extends Comparable<? super T>> int compare(T arg1, T arg2)
{
    return arg1.compareTo(arg2);
}

public static void main(String[] args)
{   
    Number i = new Integer(5);
    Number j = new Double(7);

    System.out.println(GenericsTest.compare(i, j));
}

我得到的错误消息是:绑定不匹配:GenericsTest类型的泛型方法compare(T,T)不适用于参数(Number,Number).推断类型Number不是有界参数的有效替代>

Answer 1

这个解决方案的想法是扩大到BigDecimal然后比较这两个数字(现在更清洁,但不知何故格式不起作用).请注意,您可以重复使用此静态比较器而无需在其他任何地方进行转换.在实现中,您需要转换为双倍不丢失信息,基本上您扩展到最一般的表示.

private static final Comparator<Number> NUMBER_COMPARATOR = new Comparator<Number>() {
    private BigDecimal createBigDecimal(Number value) {
        BigDecimal result = null;
        if (value instanceof Short) {
            result = BigDecimal.valueOf(value.shortValue());
        } else 
        if (value instanceof Long) {
            result = BigDecimal.valueOf(value.longValue());             
        } else 
        if (value instanceof Float) {
            result = BigDecimal.valueOf(value.floatValue());                                
        } else 
        if (value instanceof Double) {
            result = BigDecimal.valueOf(value.doubleValue());                               
        } else 
        if (value instanceof Integer) {
            result = BigDecimal.valueOf(value.intValue());                              
        } else {
            throw new IllegalArgumentException("unsupported Number subtype: " + value.getClass().getName());
        }
                       assert(result != null);

        return result;
    }

    public int compare(Number o1, Number o2) {
        return createBigDecimal(o1).compareTo(createBigDecimal(o2));
    };
};

public static void main(String[] args) {
    Number i = Integer.valueOf(5);
    Number j = Double.valueOf(7);
              // -1
    System.out.println(NUMBER_COMPARATOR.compare(i, j));

         i = Long.MAX_VALUE;
         j = Long.valueOf(7);
              // +1
         System.out.println(NUMBER_COMPARATOR.compare(i, j));

         i = Long.MAX_VALUE;
         j = Long.valueOf(-7);
              // +1
         System.out.println(NUMBER_COMPARATOR.compare(i, j));

         i = Long.MAX_VALUE;
         j = Double.MAX_VALUE;
              // -1
         System.out.println(NUMBER_COMPARATOR.compare(i, j));

    i = Long.MAX_VALUE;
    j = Long.valueOf(Long.MAX_VALUE - 1);
    // +1
    System.out.println(NUMBER_COMPARATOR.compare(i, j));

              // sorting Long values
    Long[] values = new Long[] {Long.valueOf(10), Long.valueOf(-1), Long.valueOf(4)};
    Arrays.sort(values, NUMBER_COMPARATOR);
              // [-1, 4, 10] 
    System.out.println(Arrays.toString(values));  
}