打印AWK分隔的AWK所有字段

Question

有没有办法打印OFS分隔的所有记录而不输入每个列号.

#Desired style of syntax, undesired result
[kbrandt@glade: ~] echo "1 2 3 4" | gawk 'BEGIN { OFS=" :-( "}; {print $0}'        
1 2 3 4

#Desired result, undesired syntax
[kbrandt@glade: ~] echo "1 2 3 4" | gawk 'BEGIN { OFS=" :-) "}; {print $1,$2,$3,$4}'
1 :-) 2 :-) 3 :-) 4

Answer 1

这是第一种风格的变体:

echo "1 2 3 4" | gawk 'BEGIN { OFS=" :-( "}; {$1=$1; print $0}'

结果:

1 :-( 2 :-( 3 :-( 4

说明:

该$1=$1是重建记录,使用当前OFS(你也可以看到http://www.gnu.org/software/gawk/manual/gawk.html#Changing-Fields)

更新:

(由@EdMorton和@steve建议)这是awk命令的简短版本,它在命令行中设置OFS,并利用print $0默认操作:

awk -v OFS=" :-( " '{$1=$1}1'