app*_*krb 2 java sorting android
我有两个阵列
String a[]={"11","02","43","24","05","86","37","28","29","10"};
String b[]={"a","c","f","q","w","x","z","x","s","r"};
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我想按升序对数组a []进行排序
结果可能会喜欢
String a[]={"02","05","10","11","24","28","29","37","43","86"};
String b[]={"c","w","r","a","q","x","s","z","f","x"};
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如何使用java获得上面的结果?java中可用的任何排序方法?
最简单的方法是以某种方式将2个数据链接在一起,而不是将它们放在单独的数组中.很多人都建议使用一张效果很好的地图.根据您要完成的操作,我还会考虑一个包含2个实现Comparable的变量的新类.如果没有给Collections.sort使用不同的Comparator,则Comparable定义类在Collection(在本例中为数组)时的自然顺序.它看起来像这样:
public class Data implements Comparable{
private String stringOne;
private String stringTwo;
@Override
public int compareTo(Object obj) {
stringOne.compareTo((String)obj);
}
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别的地方叫:
Collections.sort(locationOfDataCollection);
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然后,您可以创建一个数据集合,并使用getter方法访问另一个String.如果在某些情况下需要用新的比较器覆盖自然顺序(例如按stringTwo排序),这种实现也会使将来变得简单(参见策略设计).
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